problem:https://leetcode.com/contest/biweekly-contest-5/problems/connecting-cities-with-minimum-cost/ 双周赛题目。此题就是没有什么变化的最小生成树,以下给出两种经典解法: (1).并查集 首先假设所有的顶点都是一棵单独的树,之后依次选择权重最小的边,使得它连接两棵不同的树,并将两棵树合并为一棵树。...
题目地址:https://leetcode-cn.com/problems/connecting-cities-with-minimum-cost/题目描述There are N cities numbered from 1 to N.You are given connections, where each connections[i] = [city1, city2, cost] represents the cost to connect city1 and city2 together. (A connection is ...
LeetCode 1135. Connecting Cities With Minimum Cost 一道常规求minimum spanning tree的题,返回值为最小cost,出现在热带雨林厂的OA中。 难度:medium 算法:Kruskal,并查集 思路: 求MST用Kruskal或者Prim,理论上Prim在非常dense的graph中更快一点,否则Kruskal更快也更简单。 这里采用Kruskal,先对边排序,每次连最小边,...
There areNcities numbered from1toN. You are given connections, where eachconnections[i] = [city1, city2, cost]represents the cost to connectcity1andcity2together. (A connection is bidirectional: connectingcity1andcity2is the same as connectingcity2andcity1.) Return the minimum cost so that ...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/connecting-cities-with-minimum-cost 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 2. 解题 图Graph–最小生成树 1. Kruskal 将边的权值排序,小的先遍历,用并查集检查两个顶点是否合并了,没有合并则将该边加入生成树 也...
题目描述 题解 题解 提交记录 提交记录 代码 9 1 2 3 4 › 3 [[1,2,5],[1,3,6],[2,3,1]] 4 [[1,2,3],[3,4,4]] Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目 升级Plus 会员
Connecting Cities With Minimum Cost - 1584 12. Divide and Conquer Explanation The divide and conquer technique is a powerful algorithmic paradigm that involves breaking a problem down into smaller, more manageable subproblems, solving each subproblem independently, and then combining the results to solve...
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