Can you solve this real interview question? Time Needed to Buy Tickets - There are n people in a line queuing to buy tickets, where the 0th person is at the front of the line and the (n - 1)th person is at the back of the line. You are given a 0-indexed
Loop through the line of people and decrement the number of tickets for each to buy one at a time as if simulating the line moving forward. Keep track of how many tickets have been sold up until person k has no more tickets to buy. 提示2 Remember that those who have no more tickets...
总代价O(nlogn)。 2073 Time Needed to Buy Tickets 题意:有n个人排队,0是队头,n-1是队尾。tickets[i]表示第i人需要买的票数。但有个奇怪的规则,每人每次只能买1张。如果还没买够,则需要移动到队尾再排一次;如果买够了,则离开。已知每次买票需要花1s,请问第k个人买完票需要多少秒? 难度:easy 解法:...
2073-time-needed-to-buy-tickets2073 Time Needed to Buy Tickets - EasyProblem: There are n people in a line queuing to buy tickets, where the 0th person is at the front of the line and the (n - 1)th person is at the back of the line. You are given a 0-indexed integer array ...
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The truth is we only need to maintain last 30s data. Thus it couls limit dp array to 30 days. Time Complexity: O(n). Space: O(1). AC Java: 1classSolution {2publicintmincostTickets(int[] days,int[] costs) {3int[] dp =newint[30];4intind = 0;5for(inti = days[0]; i<=...
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