Can you solve this real interview question? Merge Two Sorted Lists - You are given the heads of two sorted linked lists list1 and list2. Merge the two lists into one sorted list. The list should be made by splicing together the nodes of the first two li
2、题目分析 题目要求合并有序的两个链表,要求不能额外申请空间。 3、代码 1ListNode* mergeTwoLists(ListNode* l1, ListNode*l2) {2if( l1 == NULL )returnl2;3if( l2 == NULL )returnl1;4if( l1 == NULL && l2 == NULL )returnNULL;5ListNode* r = ( l1->val <= l2->val )?l1:l2;6if...
Total Accepted:63974Total Submissions:196044My Submissions Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Show Tags Have you met this question in a real interview? Yes No Discuss 二.解题技巧 这...
改进mergeTwoLists方法,以在开始时检查空链表。 class ListNode: def __init__(self, x): self.val = x self.next = None # 改进后的将给出的数组转换为链表的函数 def linkedlist(list): if not list: # 检查列表是否为空 return None # 空列表返回None head = ListNode(list[0]) cur = head for...
# class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: # 使用一个哨兵结点 head_pre ,方便后续处理 head_pre: Optional[ListN...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路: easy 。 算法: AI检测代码解析 1. public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Seen this question in a real interview before? Yes 简单的归并排序,不说了,直接上代码:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目大意:合并两个有序的链表 思路:通过比较两个链表的节点大小,采用尾插法建立链表。 代码如下: ...
1、题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并2个有序链表 2、代码实现 /** * Definition for singly-linked list. * public class ListNode { ...
(internal/modules/run_main.js:71:12)Line 17: Char 47 in run_main_module.js这是代码:var mergeTwoLists = function(l1, l2) { let i = 0, j = 0; var out = []; while(i < l1.length || j < l2.length) { if(j == l2.length || i < l1.length && l1[i] < l2[j]) { ...