// Reuse the room: move the endIndex to the next meeting endIndex++; } else { // If no room is available, we need a new one roomCount++; } } // The room count will be the number of rooms we need return roomCount + 1; // We need at least one room } } 代码解释: 排序: ...
leetcode 扫描线专题 06-leetcode.253 meeting room ii 力扣.253 会议室 II 题目 给定一个会议时间安排的数组 intervals ,每个会议时间都会包括开始和结束的时间 intervals[i] = [starti, endi] ,请你判断一个人是否能够参加这里面的全部会议。 示例1: 输入:intervals = [[0,30],[5,10],[15,20]] 输出...
代码实现: importjava.util.*;publicclassMeetingRoomsII{publicstaticintminMeetingRooms(int[][]intervals){if(intervals.length==0){return0;}intn=intervals.length;// Step 1: Create two arrays to store the start and end timesint[]startTimes=newint[n];int[]endTimes=newint[n];for(inti=0;i<n...
--cnt_rooms;// Release a room. ++e; } } returnmin_rooms; } }; C++: minHeap 1 2 3 4 5 6 7 8 9 10 11 12 classSolution { public: intminMeetingRooms(vector<Interval>& intervals) { sort(intervals.begin(), intervals.end(), [](constInterval &a,constInterval &b){returna.start ...
leetcode 扫描线专题 06-leetcode.253 meeting room ii 力扣.253 会议室 II 题目 给定一个会议时间安排的数组 intervals ,每个会议时间都会包括开始和结束的时间 intervals[i] = [starti, endi] ,请你判断一个人是否能够参加这里面的全部会议。 示例1: ...
leetcode 扫描线专题 06-leetcode.253 meeting room ii 力扣.253 会议室 II 题目 给定一个会议时间安排的数组 intervals ,每个会议时间都会包括开始和结束的时间 intervals[i] = [starti, endi] ,请你判断一个人是否能够参加这里面的全部会议。 示例1: ...
We loop through the start pointer. Each time we have a new start, we have a new meeting. Do we need to open a new meeting room? If the end pointer pointer to a room with end time earlier, then some room will be released. We don't care which one. So we increment the end pointe...
leetcode 数组专题 06-leetcode.253 meeting room ii 力扣.253 会议室 II 什么是扫描线算法? 扫描线算法(Sweep Line Algorithm)是一种常用于解决几何问题(尤其是涉及区间、时间线或事件的重叠问题)的算法。 它的基本思想是“模拟一条扫描线从一个方向扫过所有事件”,在扫描过程中维护一个数据结构来追踪当前的状...
296 Best Meeting Point 298 Binary Tree Longest Consecutive Sequence Binary Tree Upside Down 【题目】Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tree ...
meeting room II: greedy algorithm to insert interval or see start and end as independent events. meeting point series walls and gates: BFS from the position you want to reach best meeting point: median and note that vertical direction is independent of the horizontal direction permutation combinati...