T1. 找出最大的可达成数字(Easy) https://leetcode.cn/problems/find-the-maximum-achievable-number/ 题解(模拟) 简单模拟题,在每一轮操作中可以将 num 加一,而对 x 减一,因此最大 x 就是 num + 2 * t。 classSolution{funtheMaximumAchievableX(num:Int, t:Int):Int{returnnum +2* t } } 复杂...
All buildings are full, so a list of requests is achievable only if for each building, the net change in employee transfers is zero. This means the number of employees leaving is equal to the number of employees moving in. For example ifn = 3and two employees are leaving building0, one ...
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Since every coin can be put in any combination, iterate over coins, and fill every achievable target. This will prevent the recounting of the permutations. Why? Because the definition of our state dp[i] is the number of ways to achieve a sum i using all coins. If we'll first iterate ...
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18 changes: 18 additions & 0 deletions 18 2769.find-the-maximum-achievable-number.py Original file line numberDiff line numberDiff line change @@ -0,0 +1,18 @@ # # @lc app=leetcode id=2769 lang=python # # [2769] Find the Maximum Achievable Number # # @lc code=start class Solut...
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