classSolution(object):deffindDuplicates(self, nums):""":type nums: List[int] :rtype: List[int]"""res=nums[:] res.sort()foriinnums:ifnums.count(i)==1: res.remove(i)#for j in res:#res.remove(j)#return resres=res[::2]returnres 当然后来我尝试过加入一个空数组来存放数据,如上的...
leetcode算法: Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Exa...
Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
leetcode-442.Find All Duplicates in an Array 题目Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without......
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: ...
Find all the elements of [1, n] inclusive that do not appear in this ar... 查看原文 leetcode之Find All Duplicates in an Array 问题 问题描述: Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array),some elements appear twice and others appear once. Find all the...
与[LeetCode]Find All Numbers Disappeared in an Array几乎一样,不同之处就是找出twice的数。那么我们只要当nums[i]!=i+1时,然后又当nums[nums[i]-1]==nums[i]时,把nums[i]放入set即可。
本文主要解析《Find All Numbers Disappeared in an Array》,顺便简单解释一下《Find All Duplicates in an Array》。 该题的含义是:给定一个长度为n的数组,数组元素是1~n。但是有些元素出现一次,有些元素出现两次,从而也会导致有些元素不出现。现在让我们找到哪些元素没有出现。另外一个题目是让我们找到出现两次...
请你找出所有在 [1, n] 范围内但没有出现在 nums 中的数字,并以数组的形式返回结果。 示例: 输入:nums = [4,3,2,7,8,2,3,1]输出:[5,6] 分析:这道题让我们找出数组中所有消失的数,跟之前那道Find All Duplicates in an Array极其类似,那道题让找出所有重复的数字,这道题让找不存在的数,这类...
//#442Description: Find All Duplicates in an Array | LeetCode OJ 解法1:数数。 // Solution 1: Count them. 代码1 //Code 1 444 Sequence Reconstruction // #444 序列重建 描述:给你一个序列org,再给你一堆序列seqs。按照seqs每个序列中元素的先后顺序,问是否能重建出唯一一个序列来,而且该序列就是...