Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
classSolution(object):deffindDuplicates(self, nums):""":type nums: List[int] :rtype: List[int]"""res=nums[:] res.sort()foriinnums:ifnums.count(i)==1: res.remove(i)#for j in res:#res.remove(j)#return resres=res[::2]returnres 当然后来我尝试过加入一个空数组来存放数据,如上的...
时间复杂度:O(n),空间复杂度:O(1) funcfindDuplicates(nums []int)[]int{len:=len(nums)iflen<=1{returnnil} result := []int{} i :=0fori <len{ifi == nums[i] -1|| nums[i] ==0{ i++continue}ifnums[i] == nums[nums[i] -1] { result =append(result, nums[i]) nums[i] =...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the e...[leetcode] 442. Find All Duplicates in an Array 样例: Input: Output: 在数组中找出所有重复出现的数,要求时...
LeetCode #442 - Find All Duplicates in an Array 题目描述: Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice&...[LeetCode]-442. Find All Duplicates in an Array 442. ...
问题描述: Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array),some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this ar... 查看原文 leetcode之Find All Duplicates in an Array 问题 问题描述: ...
与[LeetCode]Find All Numbers Disappeared in an Array几乎一样,不同之处就是找出twice的数。那么我们只要当nums[i]!=i+1时,然后又当nums[nums[i]-1]==nums[i]时,把nums[i]放入set即可。
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
The array may contain duplicates. 详见Leetcode Analysis Find Minimum in Rotated Sorted Array 因为题目给出的序列是相对有序,所以我们依然可以采用二分搜索的方式来查找。首先判断当前中间的那个元素是否比我们现在所拥有的最小值小,如果是这样的话,更新最小值。然后判断现在搜索区间的中心元素是否比最后一个元素...
Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear...Find all the elements that appear twice in this array. 37320 Array - 34. Find First and Last Position of Element in Sorted Array ...