题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第
889. Construct Binary Tree from Preorder and Postorder Traversal Medium Topics Companies Given two integer arrays, preorder and postorder where preorder is the preorder traversal of a binary tree of distinct values and postorder is the postorder traversal of the same tree, reconstruct and return...
1/**2* Definition for a binary tree node.3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x; }8* }9*/10classSolution11{12publicTreeNode buildTree(int[] preorder,int[] inorder)13{14Map<Integer, Integer> inMap =newHashMap<...
1classSolution:2defconstructFromPrePost(self, pre: List[int], post: List[int]) ->TreeNode:3#解法一: 递归4#前序中第二个位置的节点,即是左子树的根节点,通过这个根节点找到后序中这个节点的位置,这个即是后序中左子树的结束位置。5defbuildMyTree(pre_left, pre_right, post_left, post_right):6...
LeetCode Top 100 Liked Questions 105. Construct Binary Tree from Preorder and Inorder Traversal (Java版; Medium) 题目描述 Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. ...
题目链接:Construct Binary Search Tree from Preorder Traversal 题目大意:给定一个二叉树的前序遍历,要求给出对应的二叉搜索树 题目思路:我们可以知道,对于给定的前序遍历,遍历的顺序是前左右,所以对于一个前序序列,第一个数一定就是根节点,然后后面有一段序列是左子树,剩下的序列是右子树,又因为...
LeetCode 105. Construct Binary Tree from Preorder and Inorder Traversal Description Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given ...
https://leetcode-cn.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/solution/cong-qian-xu-yu-zhong-xu-bian-li-xu-lie-gou-zao-9/ #Java代码1 代码语言:javascript 代码运行次数:0 运行 AI代码解释 /** * Definition for a binary tree node. ...
Given preorder and inorder traversal of a tree, construct the binary tree. 二分法 复杂度 时间O(N^2) 空间 O(N) 思路 我们先考察先序遍历序列和中序遍历序列的特点。对于先序遍历序列,根在最前面,后面部分存在一个分割点,前半部分是根的左子树,后半部分是根的右子树。对于中序遍历序列,根在中间部分...
// https://leetcode-cn.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/solution/cong-qian-xu-yu-zhong-xu-bian-li-xu-lie-gou-zao-9/ struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode() : val(0), left(nullptr), right(nullptr) {} TreeNode...