}private:voidlevelOrder(TreeNode* root,intcurrLevel) {if(root == NULL)return;if(res.empty() || currLevel > (res.size() -1)) res.push_back(vector<int>()); res[currLevel].push_back(root->val); levelOrder(root->lef
下面先贴出我超时的一个算法(构造满二叉树): 1/**2* Definition for binary tree3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x; }8* }9*/10publicclassSolution {11publicList<List<Integer>>levelOrder(TreeNode root) {12List<List...
=root){val queue=LinkedList<TreeNode>()queue.offer(root)while(queue.isNotEmpty()){val levelList=mutableListOf<Int>()val size=queue.size// 此处的for循环会把当前 level 层的所有元素poll出来,同时把下一层待遍历的节点放入队列for(iin0..size-1){// removes the head (first element)...
这道题目跟上道题目很相似 Leetcode: Binary Tree Level Order Traversal ,唯一不同的就是返回结果是从子叶节点到根节点,所以我们只需要将结果翻转下就好了! 参考代码: /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : ...
leetCode 107. Binary Tree Level Order Traversal II 二叉树层次遍历反转,107.BinaryTreeLevelOrderTraversalIIGivenabinarytree,returnthe bottom-uplevelorder traversalofitsnodes'values.(ie,fromlefttoright,levelbylevelfromleaftoroot).For
这道题和LeetCode笔记:107. Binary Tree Level Order Traversal II是姊妹题,解题思路都是一样的,只是结果要求的顺序是反的,同样有两种方法,也就是经常说到的DFS深度优先遍历和BFS广度优先遍历。 BFS: 广度优先遍历就是一层层地攻略过去,把每一层的所有节点都记录下来再走向下一层。因为每层会有多个节点,不是简...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 3 / 9 20 / 15 7 return its level order traversal as: ...
Can you solve this real interview question? Binary Tree Level Order Traversal - Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level). Example 1: [https://assets.leetcode.c
Binary Tree Reconstruction(leetcode可用) Polish Notation/Reverse Polish Notation N-ary Tree 什么是树(Tree),树的概念是什么 https://www.geeksforgeeks.org/binary-tree-set-1-introduction/www.geeksforgeeks.org/binary-tree-set-1-introduction/ ...
Balanced Binary Tree 23 -- 6:11 App Leetcode-0114. Flatten Binary Tree to Linked List 89 -- 1:36 App Leetcode-0067. Add Binary 75 -- 3:26 App Leetcode-0102. Binary Tree Level Order Traversal 43 -- 4:43 App Leetcode-0095. Unique Binary Search Trees II 82 -- 6:19 ...