链接:https://leetcode-cn.com/problems/binary-tree-inorder-traversal python # 0094.二叉树中序遍历 # 递归 & 迭代 class Solution: def inOrderRecur(self,head: TreeNode) -> int: """ 递归遍历,LNR, 左根右 :param head: :return: """ def traversal(head): # 递归终止条件 ifhead== None: ...
//递归:对左子节点调用递归,访问根,对右子树调用递归classSolution{public:vector<int>inorderTraversal(TreeNode* root){ vector<int> ret;order(root,ret);returnret; }voidorder(TreeNode* root,vector<int>& ret){if(!root)return;order(root->left,ret); ret.push_back(root->val);order(root->right...
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> inorderTraversal(TreeNode* root) { vector<int> ret; if...
classSolution{publicList<Integer>inorderTraversal(TreeNode root){List<Integer>list=newArrayList<>();//数组if(root==null)returnlist;Stack<TreeNode>stack=newStack<>();//用数据结构栈暂存节点TreeNode cur=root;//定义当前节点while(!stack.isEmpty()||cur!=null){//循环条件:栈不空或当前节点不空if(...
inorder 遍历 tree 基本没难度,然后还算是 Medium... 傻逼。。。 主要考的还是非递归遍历。 代码如下: ** 总结: inorder tree ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { *...
LeetCode之“树”:Binary Tree Preorder && Inorder && Postorder Traversal,BinaryTreePreorderTraversal题目链接题目要求:Givenabinarytree,returnthepreordertraversalofitsnodes'values.Forexample:Givenbinarytree{1...
*/voidtraversal(structTreeNode*root,int*countPointer,int*res){if(!root)return;traversal(root->left,countPointer,res);res[(*countPointer)++]=root->val;traversal(root->right,countPointer,res);}int*inorderTraversal(structTreeNode*root,int*returnSize){int*res=malloc(sizeof(int)*110);intcount=...
https://leetcode.com/problems/binary-tree-inorder-traversal/ 2. 分析 2.1 迭代法 class Solution { public: vector<int> inorderTraversal(TreeNode* root) { vector<int> ans; stack<TreeNode*> todo;//定义一个栈,先入后出 ...
1. Problem Descriptions:Given two integer arrays inorderandpostorderwhereinorderis the inorder traversal of a binary tree andpostorderis the postorder traversal of the same tree, construct and retu…
val right=node.rightif(null!=left)visitLevel(ans,level+1,left)if(null!=right)visitLevel(ans,level+1,right)}classTreeNode(var`val`:Int){varleft:TreeNode?=nullvarright:TreeNode?=null} 参考资料 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/binary-tree-level-order-traversal著作...