// solve 5 : dfs + greedy + pruning var coinChange = function(coins,amount){ var res = Infinity coins.sort((a,b)=>b-a) change(amount,0,0) return res === Infinity?-1:res // 内部调用函数类 function change(amount,count,cidx){ // base case if(amount === 0){ res = Math.mi...
Leetcode 322. Coin Change 硬币找零问题 MaRin 菜鸡一只 给你一个整数数组 coins ,表示不同面额的硬币;以及一个整数 amount ,表示总金额。计算并返回可以凑成总金额所需的 最少的硬币个数 。如果没有任何一种硬币组合能组成总金额,返回 -1 。你可以认为每种硬币的数量是无限的。对应leetcode链接为: https:/...
intcoinChange(vector<int>& coins,intamount) { if(!coins.size() && amount) return-1; vector<int> dp(amount + 1, INT_MAX); dp[0] = 0; for(autocoin : coins) { for(inti = coin; i <= amount; ++i) { if(dp[i-coin] != INT_MAX) { dp[i] = min(dp[i], dp[i - coin]...
publicclassSolution {publicintcoinChange(int[] coins,intamount ) {if(amount==0)return0;int[] ret =newint[ amount + 1];for(inti = 1; i <= amount; i++) {intmin =i;for(intj = 0; j < coins.length; j++) {if( i >=coins[ j ] ) {if(i==coins[j]){ ret[i]= 1; } /...
You may assume that you have an infinite number of each kind of coin. Credits: Special thanks to@jianchao.li.fighterfor adding this problem and creating all test cases. 这道题给我们了一些可用的硬币值,又给了一个钱数,问我们最小能用几个硬币来找零。根据题目中的例子可知,不是每次都会给全1,...
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LeetCode: 322. Coin Change 题目描述 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins...
Coin Change 题目: You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of mo...LeetCode 322. Coin Change You are given coins of different ...
Can you solve this real interview question? Coin Change - You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to m
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