https://leetcode-cn.com/problems/coin-change 解题思路 动态规划,自底向上,太简单,不解释。 C++代码 classSolution{public:intcoinChange(vector<int>& coins,intamount){vector<int>dp(amount +1, amount +1); dp[0] =0;for(inti =1; i <= amount; i++) {for(autov : coins) {if(i >= v)...
// solve 5 : dfs + greedy + pruning var coinChange = function(coins,amount){ var res = Infinity coins.sort((a,b)=>b-a) change(amount,0,0) return res === Infinity?-1:res // 内部调用函数类 function change(amount,count,cidx){ // base case if(amount === 0){ res = Math.mi...
依次向前推,直到r等于0或者小于0. public int coinChange(int[] coins, int amount) { if (amount < 0) return 0; return coinChangeCore(coins, amount, new int[amount]); } private int coinChangeCore(int[] coins, int amount, int[] count) { if (amount < 0) return -1; if (amount ==...
Can you solve this real interview question? Coin Change - You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to m
322--Coin Change比较清晰的动态规划,状态转移方程和起始状态都是比较好找到的,但需要一系列的学习才能对这类动态规划问题熟悉。我会继续上传这个问题的变式的解法。, 视频播放量 49、弹幕量 0、点赞数 2、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 Nemesiscs, 作
leetcode的testcase有一个为amount为0的时候,所以在代码的开头加了一个判断。 吐槽一下leetcode怎么有这么多诡异的testcase。 classSolution:defcoinChange(self,coins:List[int],amount:int)->int:ifamount==0:return0dp=[amount+1]*(amount+1)dp[0]=0foriinrange(1,amount+1):forcincoins:ifi>=c:dp...
https://leetcode-cn.com/problems/coin-change/description/给定不同面额的硬币 coins 和一个总金额amount。编写一个函数来计算可以凑成总金额所需的最少的硬币个数。如果没有任何一种硬币组合能组成总金额,返回 -1。示例1:输入: coins = [1, 2, 5], amount = 11 输出: 3 解释: 11 = 5 + 5 + 1...
leetcode322. Coin Change 题目要求 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, ...
LeetCode: 322. Coin Change 题目描述 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins...
leetcode 518. Coin Change 2 一、题意 给一个整数数组 coins 表示不同面额的硬币,另给一个整数 amount 表示总金额。 请计算并返回可以凑成总金额的硬币组合数。如果任何硬币组合都无法凑出总金额,返回 0 。 假设每一种面额的硬币有无限个。 题目数据保证结果符合 32 位带符号整数。 二、解法 解法: 动态...