publicclassSolution { publicListNode addTwoNumbers(ListNode l1, ListNode l2) { //如果给出就为空,则直接返回另外一个链表 if(l1 ==null)returnl2; if(l2 ==null)returnl1; intflag =0;//存放进位信息,但是并不是处理最后的进位标志 //构造返回结果的第一个
public static double ListToNumber(ListNode head) { if (head == null) return 0; double num = 0; double base = 1; while (head != null) { num += head.val * base; head = head.next; base = base * 10; } return num; } Solution 2(推荐) public ListNode addTwoNumbers(ListNode l1,...
思路展示 图片、答案思路来源: https://leetcode-cn.com/problems/add-two-numbers/solution/liang-shu-xiang-jia-by-leetcode/ 我们将跟踪逐位计算过程,逐位相加满 10 取余数作为结果,并进位 1 给下一节点相加,逐位将结果连为链表。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution:defadd...
最终代码: /*** Definition for singly-linked list.* public class ListNode {* public int val;* public ListNode next;* public ListNode(int x) { val = x; }* }*/publicclassSolution{publicListNodeAddTwoNumbers(ListNodel1,ListNodel2){ListNodehead=newListNode(0);ListNodel3=head;ListNodel4=l3;int...
Add Two Numbers 感谢python的整数相加无上界...【LeetCode】2. Add Two Numbers 传送门:https://leetcode.com/problems/add-two-numbers/ 一、题目描述 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their node....
class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: link1 = l1 link2 = l2 while(link1!=None and link2 !=None): a = link1.val link2.val += a link1.val = link2.val link1 = link1.next
[LeetCode-02]-Add Two Numbers-性能极好 文章目录 题目相关 Solution 1. 错误的解法 2. 正确解法 3. 几个用例 后记 每周完成一个ARTS:(Algorithm、Review、Tip、Share, ARTS) Algorithm: 每周至少做一个 leetcode 的算法题 Review: 阅读并点评至少一篇英文技术文章 Tip: 学习至少一个技术技巧 Share: 分享...
LeetCode 2. Add Two Numbers non-empty You may assume the two numbers do not contain any leading zero, except the number 0 itself. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: answer: class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {...
public class Solution { /* * 方法1 */ public static ListNode addTwoNumbers(ListNode l1,ListNode l2) { //如果都为空 直接返回不为空的一个参数 如果都未空 则返回空 if(l1 == null || l2 == null){ return l1 == null ?(l2 == null ?null:l2):l1; ...
# class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ stack1 = [] stack2 = [] while l1: stack1.append(l1.val) ...