Python 中也没有链表这个概念和结构,是要自己定义吗?尤其是看到答题区默认的格式: 代码语言:javascript 复制 # Definitionforsingly-linked list.#classListNode:# def__init__(self,x):# self.val=x # self.next=NoneclassSolution:defaddTwoNumbers(self,l1:ListNode,l2:ListNode)->ListNode: 先看注释部分,这...
/usr/bin/python32#-*- coding: utf-8 -*-3#@author: Albert4#@Time: 2018/8/13567classListNode(object):8def__init__(self, x):9self.val =x10self.next =None1112classSolution(object):13defaddTwoNumbers(self, l1, l2):#求解14"""15:type l1: ListNode16:type l2: ListNode17:rtype: Lis...
也就是说有2个类,Solution 和 ListNode 今天先这样了,我需要去学习一下什么是“类”,也就是Python的
x):#self.val = x#self.next = NoneclassSolution:defaddTwoNumbers(self, l1: ListNode, l2: ListNode) ->ListNode:#首先对两个链表进行遍历,然后将数字转化为字符串加起来#然后对整个字符串进行逆序,在逆序的同时赋值给新创建的链表#首先考虑为0的情况#考虑链表不为0的情况l1_node=[] ...
class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: # 初始化个位节点,先不做进位 newPoint = ListNode(l1.val + l2.val) # rt用来作为最后return的节点,tp用来遍历节点 rt, tp = newPoint, newPoint # l1,l2只要后面还有节点,就继续往后遍历;或者新链表还需要继续往后...
class Solution(object): def addTwoNumbers(self, l1, l2): resultNode = None add = 0 while True: if l1.val == -1: l1.val = 0 if l2.val == -1: l2.val = 0 tSum = (l1.val + l2.val + add) % 10 add = (l1.val + l2.val + add) / 10 ...
nullptr : l2->next; } return ret; }};Python Code:# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = Noneclass Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: def listToSt...
# self.val = val # self.next = next classSolution(object): defaddTwoNumbers(self,l1,l2): ifnotl1: returnl2 ifnotl2: returnl1 s1,s2='','' whilel1: s1+=str(l1.val) l1=l1.next whilel2: s2+=str(l2.val) l2=l2.next
class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: # 定义个result result = ListNode(); result_return = result; # 存储 进位 plus_next = 0; # 循环体 while l1 != None or l2 != None: ...
def twoSum(nums, target): """ Finds two numbers such that they add up to a specifi...