代码实现: 1classSolution {2public:3ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {4ListNode preHead(0), *p = &preHead;5intcarry =0;6while(l1 || l2 ||carry) {7intsum = (l1 ? l1->val :0) + (l2 ? l2->val :0) +carry;8carry = sum /10;9p->next =newListNode(sum ...
public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode result = new ListNode(0); ListNode tem = l1; ListNode tem2 = l2; ListNode current = result; boolean flag = false; while (tem != null || tem2 != null) { // 计算节点值之和,需要判空 int sum = (tem != null ?
Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. 翻译 给定两个非空的链表,代表两个非负整数。这两个整数都是倒叙存储,要求返回一个链表,表示这两个整数的和。 样例 Input: (2 -> 4 -> 3) +...
AI代码解释 classSolution{public:ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){ListNode*ret=newListNode();ListNode*pnt=ret;bool carry=false;while(l1!=nullptr||l2!=nullptr||carry){int cur=0;if(l1!=nullptr){cur+=l1->val;l1=l1->next;}if(l2!=nullptr){cur+=l2->val;l2=l2->next;}if(...
LeetCode 2 Add Two Numbers——用链表模拟加法 点击上方蓝字,和我一起学技术。 今天要讲的是一道经典的算法题,虽然不难,但是很有意思,我们一起来看下题目: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their ...
def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: link1 = l1 link2 = l2 while(link1!=None and link2 !=None): a = link1.val link2.val += a link1.val = link2.val link1 = link1.next link2 = link2.next ...
LeetCode(2):Add Two Numbers 两数相加 Medium! 题目描述: 给定两个非空链表来表示两个非负整数。位数按照逆序方式存储,它们的每个节点只存储单个数字。将两数相加返回一个新的链表。 你可以假设除了数字 0 之外,这两个数字都不会以零开头。 示例:
public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode dummy = new ListNode(0); ListNode cur = dummy; int carry = 0; while (l1 != null || l2 != null || carry != 0) { int i1 = l1 != null ? l1.val : 0; ...
[LeetCode] 2. Add Two Numbers 两个数字相加Grandyang刷尽天下 立即播放 打开App,流畅又高清100+个相关视频 更多157 -- 9:59 App [LeetCode] 1. Two Sum 两数之和 126 -- 9:53 App [LeetCode] 82. Remove Duplicates from Sorted List II 删除排序链表中的重复元素之二 149 -- 20:30 App [...
LeetCode之Add Two Numbers 方法一: 考虑到有进位的问题,首先想到的思路是: 先分位求总和得到 totalsum,然后再将totalsum按位拆分转成链表; 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){2int sum=0;3int i=1;4while(l1!=NULL&&l2!=NULL)5{6...