O(n)时间 leetcode一次通过。 public static ListNode addTwoNumbers(ListNode l1, ListNode l2) { if (l1 == null && l2 == null) return null; double num1 = ListToNumber(l1); double num2 = ListToNumber(l2); return NumberToList(num1 + num2); } public static ListNode NumberToList(double...
2 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. 3 You may assume the two numbers do not contain any leading zero...
Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. 翻译 给定两个非空的链表,代表两个非负整数。这两个整数都是倒叙存储,要求返回一个链表,表示这两个整数的和。 样例 Input: (2 -> 4 -> 3) +...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, exc...
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关于第二步两个数组相加,一开始的思路并不是这样的,而是转成String再转Number相加再转回来,那么这个思路折哪儿了呢,有一个测试用例是[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1]和[5,6,4],转成Number相加得1e+30,没错,万恶的弱类型,查询能不能不转换...
请你将两个数相加,并以相同形式返回一个表示和的链表。你可以假设除了数字 0 之外,这两个数都不会以 0 开头。 示例 addtwonumber1 示例一输入:l1 = [2,4,3], l2 = [5,6,4] 输出:[7,0,8] 解释:342 + 465 = 807. 示例二输入:l1 = [0], l2 = [0] 输出:[0] 示例三输入:l1 = [9,...
You may assume the two numbers do not contain any leading zero, except the number 0 itself. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 题意不讲了,直接上答案。 这道题给的启示就是注意头结点head的设置,设置了head结点,就可以避免当前节点为null的情况,否者无法...
id=445 lang=javascript * * [445] Add Two Numbers II *//** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } *//** * @param {ListNode} l1 * @param {ListNode} l2 * @return {ListNode} */var addTwoNumbers...
Output: 思路: 对齐链表,注意尾结点如果计算有进位要新生成一个结点记录。 算法: public int getListLength(ListNode head) { int length = 0; ListNode p = head; while (p != null) { length++; p = p.next; } return length; } public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ...