LeetCode.2-两个数字相加(Add Two Numbers) 这是悦乐书的第340次更新,第364篇原创01 看题和准备今天介绍的是LeetCode算法题中Medium级别的第1题(顺位题号是2)。给定两个非空链表,表示两个非负整数。 数字以相反的顺序存储,每个节点包含一个数字。将两个数字相加并将其作为链表返回。你可以假设这两个数字不包
AI代码解释 publicstaticListNodeaddTwoNumbers(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode head=newListNode(0);ListNode point=head;int carry=0;while(l1!=null&&l2!=null){int sum=carry+l1.val+l2.val;ListNode rest=newListNode(sum%10)...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. 你有两个非空链表,表示两个非负整数,数字以相反的顺序存储,每个节点中包...
classSolution {publicListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode l3=null;booleanadd =false;while(l1 !=null|| l2 !=null) {//位数相加intplus;if(l1 ==null) { plus=l2.val; }elseif(l2 ==null) { plus=l1.val; }else{ plus= l1.val +l2.val; }if(add) { plus++; ...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, exc...
【LeetCode】2. Add Two Numbers 两数相加 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:两数相加,链表,求加法,题解,leetcode, 力扣,python, c++, java 目录 题目描述
[Leetcode] Add Two Numbers 链表数相加 Add Two Numbers You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
“Add Two Numbers” 是一个中等难度的问题,涉及链表的操作。 这个问题的描述是:你有两个非空的链表,代表两个非负的整数。它们的每个节点都包含一个数字。数字以相反的顺序存储,每个节点包含一个数字。你需要将这两个数相加,并将它们作为一个链表返回。 问题的关键在于处理链表的遍历和进位。下面是使用 Java 实...
LeetCode 2 Add Two Numbers——用链表模拟加法 点击上方蓝字,和我一起学技术。 今天要讲的是一道经典的算法题,虽然不难,但是很有意思,我们一起来看下题目: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their ...
Anwser 1: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { ...