node.value = i; pointer.next = node; pointer = pointer.next; }returnlist; }publicstaticvoidmain(String[] args){RotateListrotateList=newRotateList(); print(rotateList.rotate(generateList(5),5)); print(rotateList.rotate(generateList(5),2)); print(rotateList.rotate(generateList(5),0)); ...
具体代码如下: 1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, x):4#self.val = x5#self.next = None67classSolution:8#@param head, a ListNode9#@param k, an integer10#@return a ListNode11defrotateRight(self, head, k):12ifk==0orhead==Noneorhead.next==Non...
示例 1: 输入: 1->2->3->4->5->NULL, k = 2 输出: 4->5->1->2->3->NULL 解释: 向右旋转 1 步: 5->1->2->3-&g...LeetCode 20200203(旋转链表) 1.旋转链表 这道题做过一遍了 很简单 就是对链表的基本操作 计算链表的长度 然后找到要截断的地方 进行重组 记得写一个虚拟头结点 ...
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode rotateRight(ListNode head, int k) { // 边界情况处理 if (head == null) { return head; } // 统计链表长度...
leetcode Rotate List 1. 题目描述 Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given 1->2->3->4->5->NULL andk= 2, return 4->5->1->2->3->NULL....
0 <= k <= 2 * 109 2. 解法 # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def rotateRight(self, head: ListNode, k: int) -> ListNode: if k == 0 or not head or not...
LeetCode题解:Rotate List Rotate List Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given1->2->3->4->5->NULLandk=2, return4->5->1->2->3->NULL. 思路: 这个题目的陷阱中,输入为空指针大约不算其中之一。主要的问题是k可以大于这个链表的总...
https://leetcode.com/problems/remove-duplicates-from-sorted-list/ https://leetcode.com/problems/subarray-product-less-than-k/ https://leetcode.com/problems/backspace-string-compare/ https://leetcode.com/problems/squares-of-a-sorted-array/ ...
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode* rotateRight(ListNode* head, int k) { 12 if(head == NULL) ...
Rotate List Medium java 92 Reverse Linked List II Medium java 206 Reverse Linked List Easy java 合并链表 例题:21 Merge Two Sorted Lists 【easy】 题意:将两个排序好的链表合并成新的有序链表 test case: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 解题思路: 迭代法和...