classSolution{public:vector<int>intersection(vector<int>& nums1, vector<int>& nums2){sort(nums1.begin(), nums1.end());sort(nums2.begin(), nums2.end());// merge two sorted arraysvector<int> ret;inti =0, j =0;while(i < nums1.size() && j < nums2.size()) {if(nums1[i] ...
LeetCode题解之 Intersection of Two Arrays 1、题目描述 2、问题分析 借助于set来做。 3、代码 1 class Solution { 2 public: 3 vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { 4 vector<int> res; 5 set<int> s1; 6 set<int> s2; 7 for( auto & n : nums1) 8 s1...
What if the given array is already sorted? How would you optimize your algorithm? What if nums1’s size is small compared to nums2’s size? Which algorithm is better? What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into ...
What if the given array is already sorted? How would you optimize your algorithm? What ifnums1's size is small compared tonums2's size? Which algorithm is better? What if elements ofnums2are stored on disk, and the memory is limited such that you cannot load all elements into the memo...
What if the given array is already sorted? How would you optimize your algorithm? What if nums1's size is small compared to num2's size? Which algorithm is better? What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the...
//leetcode.com/discuss/interview-question/914249/Uber-or-Phone-or-Union-and-Intersection-of-Two-Sorted-Interval-Lists */ public class UnionAndIntersectionOfTwoSortedIntervalLists { public static void main(String[] args) { } public int[][] intersectionOfTwoIntervals(int[][] a, int[][] b) ...
Golang Leetcode 349. Intersection of Two Arrays.go 思路 用map保存第一个数组的元素,然后遍历第二个数组,如果已经在map中存在,就添加到结果集 code 代码语言:javascript 复制 funcintersection(nums1[]int,nums2[]int)[]int{m:=make(map[int]bool)for_,v:=range nums1{m[v]=true}ret:=[]int{}for...
349. Intersection of Two Arrays # 题目 # Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each
LeetCode – Intersection of Two Arrays (Java) Given two arrays, write a function to compute their intersection. Java Solution 1 – HashSet Time = O(n). Space = O(n). publicint[]intersection(int[]nums1,int[]nums2){HashSet<Integer>set1=newHashSet<Integer>();for(inti:nums1){set1....
这道题是之前那道Intersection of Two Arrays的拓展,不同之处在于这道题允许返回重复的数字,而且是尽可能多的返回,之前那道题是说有重复的数字只返回一个就行。那么这道题用 HashMap 来建立 nums1 中字符和其出现个数之间的映射, 然后遍历 nums2 数组,如果当前字符在 HashMap 中的个数大于0,则将此字符加入...