classSolution{public:vector<int>intersection(vector<int>& nums1, vector<int>& nums2){sort(nums1.begin(), nums1.end());sort(nums2.begin(), nums2.end());// merge two sorted arraysvector<int> ret;inti =0, j =0;while(i < nums1.size() && j < nums2.size()) {if(nums1[i] ...
LeetCode题解之 Intersection of Two Arrays 1、题目描述 2、问题分析 借助于set来做。 3、代码 1 class Solution { 2 public: 3 vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { 4 vector<int> res; 5 set<int> s1; 6 set<int> s2; 7 for( auto & n : nums1) 8 s1...
What if the given array is already sorted? How would you optimize your algorithm? What if nums1’s size is small compared to nums2’s size? Which algorithm is better? What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into ...
Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must appear as many times as it shows in both arrays and you may return the result in any order. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] ...
//leetcode.com/discuss/interview-question/914249/Uber-or-Phone-or-Union-and-Intersection-of-Two-Sorted-Interval-Lists */ public class UnionAndIntersectionOfTwoSortedIntervalLists { public static void main(String[] args) { } public int[][] intersectionOfTwoIntervals(int[][] a, int[][] b) ...
return A A = A.next B = B.next return None 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 然后用了这个题解 class Solution: # @param two ListNodes # @return the intersected ListNode def getIntersectionNode(self, headA, headB): ...
What if the given array is already sorted? How would you optimize your algorithm? What if nums1's size is small compared to num2's size? Which algorithm is better? What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the...
What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once? 思路: Solution 1: 这道题就是Intersection of Two Arrays的加强版。同样用HashMap来做。需要考虑在intersection中重复的次数。 代码如下: public class Solution ...
Leetcode:Question4--Median of Two Sorted Arrays 题目描述 解法 这道题目假如采取最普通的做法,即为将两个数组结合在一起,再进行排序,然后取出直接取出中位数即可。排序的算法最优复杂度为 O(nlogn),而取出中位数的复杂度为O(n),遍历两个数组的复杂度也是O(n),所以整个算法的复杂度为O(nlogn),明显...
LeetCode笔记:350. Intersection of Two Arrays II 问题: Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times a......