Integrate: \int cosxe^{sinx} dx Integrate: \int(ln x + l) \sqrt {(x \cdot ln x)^2 + 1} dx Integrate: \int \frac{3x}{4+x^2} dx Integrate: \int 3x^2\sqrt{x^3 + 1} dx Integrate: \int_0^{0.6} \frac{x^2}{\sqrt{9 - 25x^2 dx ...
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Step 3: IntegrateNow we can integrate −∫sin(t)dt:−∫sin(t)dt=−(−cos(t))+C=cos(t)+C Step 4: Substitute BackNow, we substitute back t=cosx:cos(t)+C=cos(cosx)+C Final AnswerThus, the integral of sinxsin(cosx)dx is:∫sinxsin(cosx)dx=cos(cosx)+C Show More ...
Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx Evaluate the indefinite integral of sin(x) cos(x) dx using integration by parts How to integrate sqrt(1 - cos(x)) Integrate the given function. integral 5 sin^2 x dx ...
Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx cos 5x sin 3x. Integrate with respect to x. Integrate the following using integration by parts integral x 2 sin 5 x d x Integrate a) \int x^2 \sin {(2x)} dx b) \int \sqrt {2 + \cos {(3x) \sin {(3x)} dx ...
{eq}\begin{align} \int \frac{ x - 2 }{ \left( x^2 - 4x + 3 \right)^5} dx &=?? \end{align} {/eq} Solution Let... Learn more about this topic: Indefinite Integrals as Anti Derivatives from Chapter 12/ Lesson 11 17K ...
Answer to: Integrate (a) \int sinxdx (b) \int sin^{2}xdx (c) \int sinxcosxdx (d) \int sin^{3}dx By signing up, you'll get thousands of step-by-step...
Integrate : int log(sinx).cosx dx 03:11 সমাকল করো:inte^x(cosx-sinx)dx 01:26 সমাকল করো:int(dx)/(sinx+cosx) 02:00 সমাকল করো:int(1+sinx)/(sinx (1+cosx))dx 04:40 Find the following integral: int(sinx+cosx)dx 01...
Integrate: integral_0^pi/2 (sinx + cosx)^2 Integrate 1/sinx Integrate: int; x sin x dx Evaluate: Integration of {(sin^3 (x))(cos^2 (x))} dx Evaluate the integral: integral_0^pi/3 sin^3 3x dx Integrate. 1 multiplied by (8 - sin x) dx Find the indefinite integral: \int ...
Integrate the functions e^(x)((1+sinx)/(1+cosx)) 06:05 Integrate the following functions : e^(x)((1+xlogx)/(x)) 00:55 int(logx+(1)/(x^(2)))e^(x)dx=...+c 03:21 int(x^(6)+7x^(5)+6x^(4)+5x^(3)+4x^(2)+3x+1)e^(x)dx=...+c 02:47 intxcos2xdx=......