Integrate \int cos(x) cos^5 (sin(x)) dx Integrate. \int (8 - \sin x)dx Evaluate the integral from 0 to pi/2 of [sin(x) + 1]^5 cos(x) dx Evaluate the integral. integral (sin^3 x cos x - sin^2 x + 1) dx Integrate: \int (2 sec^2 x + 3 sin (2 \pi x)) dx...
sinxdx=−dt Step 2: Rewrite the IntegralNow, we can rewrite the integral ∫sinxsin(cosx)dx using our substitution:∫sinxsin(cosx)dx=∫sinxsin(t)dxSubstituting for sinxdx:=∫sin(t)(−dt)=−∫sin(t)dt Step 3: IntegrateNow we can integrate −∫sin(t)dt:−∫sin(t)dt=−(...
Answer to: Integrate (a) \int sinxdx (b) \int sin^{2}xdx (c) \int sinxcosxdx (d) \int sin^{3}dx By signing up, you'll get thousands of step-by-step...
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Integrate the following: (1) \int \frac{cosx}{5-3sinx}dx (2) \int e^{tanx}sec^{2}dx integrate the following: \int \frac{75}{x^2+25} dx Integrate the following: { \int \frac{sin^3 x}{cosx} } Integrate the following. int e^x (1 + x ln (x)) over x Integrate the fol...
Let u = sinx. Then du = cos x dx.The integral becomes:du/ (u^2 + 9)Next, 9 is factored out of the denominator:1/9 integeral du / ( (1/3u)^2 + 1)This is merely the derivative of the arctan function arctan(z) where z = 1/3u...
Integrate (6x - \frac {2}{(3x^2-2x)^5} )dx Integrate: \int_1^4 \frac {1}{\sqrt x (\sqrt x + 1)^2} dx Integrate \frac {sinx}{(sinx+cosx)} dx Determine the indefinite integral below. \int \frac {dx}{x^9}\ \int \frac {dx}{x^9}=\Box Integrate the following. a...
Integrate: \int cosxe^{sinx} dx Integrate: \int(ln x + l) \sqrt {(x \cdot ln x)^2 + 1} dx Integrate: \int \frac{3x}{4+x^2} dx Integrate: \int 3x^2\sqrt{x^3 + 1} dx Integrate: \int_0^{0.6} \frac{x^2}{\sqrt{9 - 25x^2 dx ...
Integrate: \int cosxe^{sinx} dx Integrate \int_{0}^{\frac{\pi}{4sin (2x) sin (x) dx Integrate xe^x dx Integrate: \int \frac{3x}{4+x^2} dx Integrate: \int \frac{x^2-8x }{x+2} dx Integrate (15^x/3^x) dx Integrate: \int_{-1}^1 x^2 \sqrt {x^3 + 1} dx In...
Integrate : int log(sinx).cosx dx 03:11 সমাকল করো:inte^x(cosx-sinx)dx 01:26 সমাকল করো:int(dx)/(sinx+cosx) 02:00 সমাকল করো:int(1+sinx)/(sinx (1+cosx))dx 04:40 Find the following integral: int(sinx+cosx)dx 01...