Now, we can rewrite the integral ∫sinxsin(cosx)dx using our substitution:∫sinxsin(cosx)dx=∫sinxsin(t)dxSubstituting for sinxdx:=∫sin(t)(−dt)=−∫sin(t)dt Step 3: IntegrateNow we can integrate −∫sin(t)dt:−∫sin(t)dt=−(−cos(t))+C=cos(t)+C Step 4: ...
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Integrate : int log(sinx).cosx dx 03:11 সমাকল করো:inte^x(cosx-sinx)dx 01:26 সমাকল করো:int(dx)/(sinx+cosx) 02:00 সমাকল করো:int(1+sinx)/(sinx (1+cosx))dx 04:40 Find the following integral: int(sinx+cosx)dx 01...