Find the integralintsecx(secx+tanx)dx 01:34 Evaluate: int (sec ^(2) x)/(cosec ^(2) x) dx 01:23 int (2-3 sin x)/(cos^(2) x) dx 02:27 The anti derivative of (sqrt(x)+1/(sqrt(x)))equals(A) 1/3x^(1/3)+2x^(1... 01:32 If d/(dx)f(x)=4x^3-3/(x^4)such...
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we will use the substitution t=secx+tanx. Step 1: Substitute t=secx+tanx From the identity sec2x=1+tan2x and the derivative of t: dtdx=secxtanx+sec2x=sec2x+secxtanx. Thus, we can express dx in terms of dt: dx=dtsec2x+secxtanx. Step 2: Rewrite sec2x+secxtanx Using our substitut...
Evaluate the integral: \int tan^{3}x\ secx\ dx. Evaluate the indefinite integral of sec^3(x) tan (x) dx Find the indefinite integral of \int sec \ y (\tan y - sec \ y) \ dy. Find the indefinite integral by using the substitution x = 9 \sec (\theta). (Use ...
2.8万 35 7:24 App 有理函数不定积分4 Integral of 1/(x^6 + 1) dx 1.9万 20 4:25 App 求不定积分 Integral of Sqrt[tanx] dx 1.7万 24 4:52 App 多种方法计算积分 Integral of secx dx 2.2万 20 5:26 App 计算sin18°, cos18°, sin36°, cos36°, sin54°, cos54°, sin72°...
Compute the indefinite integral ∫esinx(xcosx−tanxsecx) dx. Integration By Parts: We write the integral as the sum of two integrals. We calculate each of these integrals by using the integration by parts. We add up the results and simplify. Answer and Explanation: We have {eq...
∫secxdx ln|secx + tanx| + C ∫e^u du e^u + C ∫cscxdx -ln|cscx+cotx| + C d/dx [a^x] (a^x) * ln a d/dx aᵘ aᵘ (ln a) du/dx d/dx [log a (x)] 1/(x * ln a) ∫a^x dx a^x/ln(a) + C d/dx [log a (u)] u'/ (u * ln a) c^a= x, conv...
Evaluate the integral from 0 to 3/2 of 1/(sqrt(9 - x^2)) dx. Evaluate the integral. xsecxtanx Evaluate the integral. \int_{0}^{1}\frac{\ln x}{\sqrt{xdx Evaluate integral of \int\frac{e^{x^{\frac{1}{2{x^{\frac{1}{2}dx. Evaluate the definite integral \int_{0...
常用积分表（Common integral table）Common integral formula (a) containing the integral (axb+0a =) Formula 1.dxaxb+ = 1lnaxbCa++ 2. = (axbx) + 11 (formula)(1)AxbCa + + + Mu + (U = 1.)3.dxxaxb+ = formula 21 (LN) axbbaxbCa+.++ The 4.2dxxaxb+ formula (2) = 22311 (...
tanx + c ∫csc²xdx -cotx + C ∫secxtanx secx + c ∫cscxcotx -cscx + c ∫e^x dx e^x + C ∫(1/x)dx ln|x| + C ∫a^x dx (a^x/ln a) + C ∫1/√(1-x²)dx sin⁻¹x + C ∫-1/√(1-x²) dx = ...