2.8万 35 7:24 App 有理函数不定积分4 Integral of 1/(x^6 + 1) dx 1.9万 20 4:25 App 求不定积分 Integral of Sqrt[tanx] dx 1.7万 24 4:52 App 多种方法计算积分 Integral of secx dx 2.2万 20 5:26 App 计算sin18°, cos18°, sin36°, cos36°, sin54°, cos54°, sin72°...
1158 1 4:16 App 求不定积分 ∫(sec^2 x)/(secx + tanx)^(9/2) dx 1722 -- 5:32 App 求不定积分∫Sqrt[x^2 - 2 x + 2] dx 3248 2 3:01 App 比较简单的积分练习题 Integral of sin (lnx) dx 7643 6 4:32 App 求所有的质数 p, q ,满足 p^q + q^p 是质数 7224 10 3...
∫1secx+tanxdx= View Solution ∫secxlog(secx+tanx)dx= View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
A) Integral of (dx)/(2*sqrt(x) + 2x). B) Integral of tan(x) ln(cos(x)) dx. What is the integral of 1/tan(x) dx? Evaluate: the integral of tan^2(x) sec^4(x) dx. Evaluate the integral: \int tan^{3}x\ secx\ dx. Find the integral of (-x^2 + 2x -...
{eq}\displaystyle \int_{0}^{\frac{\pi }{2}}\sin ^{3}\ x\cos ^{2}\ x \ dx {/eq} Compute the indefinite integral: {eq}=\displaystyle... Learn more about this topic: Applying the Rules of Differentiation to Calculate Derivatives ...
Compute the indefinite integral \int e^{sin x}(xcosx-tanxsecx) dx. Evaluate the indefinite integral integral sec 3 x tan x d x Integrate: integral tan\ 4x dx Find the indefinite integral using the substitution x = tan theta. integral {1} / {x^2 square root {...
常用积分表（Common integral table）Common integral formula (a) containing the integral (axb+0a =) Formula 1.dxaxb+ = 1lnaxbCa++ 2. = (axbx) + 11 (formula)(1)AxbCa + + + Mu + (U = 1.)3.dxxaxb+ = formula 21 (LN) axbbaxbCa+.++ The 4.2dxxaxb+ formula (2) = 22311 (...
函数secxtan 无法识别您的输入,请检查。不定积分计算器可以用分析整合的方法,计算出一个给定变量的函数的不定积分(原函数)。它也可以画出函数和它的原函数的图像。请注意,计算的不定积分属于一类函数F(x) C,其中C是任意常数。不定积分计算器解析表达式,应用积分法则并化简最终结果。因此,积分计算的最终结果可能...
87.secdxx∫=lntan () 42xcπ + + + + =lnsectanxxc 88.cscdxx∫=lntan2xc + =lncsccotxxc. + 89.2secdxx∫=tanxc + 90.2cscdxx∫=cotxc. + 91.sectandxxx∫=secxc + 92.csccotdxxx∫=cscxc. + 93.2sindxx∫=1sin224xxc. + ...
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