Evaluate the following integral: Integral of sec^6(x) * tan(x) dx. Evaluate the integrals. A) Integral of (dx)/(2*sqrt(x) + 2x). B) Integral of tan(x) ln(cos(x)) dx. Evaluate the indefinite integral. { \int sec^3x tanx dx } Evaluate the indefinite integral. (Use C for...
Use integration by parts to find the integral of:[Hint: In (7) write lnx as 1lnx and in (9) write arctanxdn as 1arctanax.](1)xe^x(2)xsinx(3)x^2lnx(4)xsin3x(5)xcos2x(6)xsec^2x(7)lnx(8)(lnx)^2(9)arctanxdn ...
I=∫sec2x(secx+tanx)9/2dx, we will use the substitution t=secx+tanx. Step 1: Substitute t=secx+tanx From the identity sec2x=1+tan2x and the derivative of t: dtdx=secxtanx+sec2x=sec2x+secxtanx. Thus, we can express dx in terms of dt: dx=dtsec2x+secxtanx. Step 2: Rewrite se...
int (sec^2 (t) i + t(t^2+1)^8j+t^2 ln (t) k) dt Evaluate the indefinite integral. { \int sec^3x tanx dx } Evaluate each integral. \displaystyle\int_{\frac{x}{3^{x}\frac{\sin x}{\sqrt{3+2\cos xdx Evaluate the integral of \sin^4 xdx Find: Form the integration \in...
Name of the Concept Formulae 1 Integral formulas ∫ xndx=(xn+1/n+1)+C, where n ≠ -1 ∫ dx =x+C ∫ cos x dx = sin x + C ∫ sin x dx = -cos x + C ∫ sec2x dx = tan x + C ∫ cosec2x dx = -cot x + C ...
Integral from 2*sqrt(2) to 4 of 1/(t^3 sqrt(t^2 - 4)) dt. Evaluate the integral from 0 to 3/2 of 1/(sqrt(9 - x^2)) dx. Evaluate the integral. xsecxtanx Evaluate the integral. \int_{0}^{1}\frac{\ln x}{\sqrt{xdx Evaluate integral of \int\frac{e^{x^{\fra...
Answer to: Evaluate the integral \int_1^4 (x^2-5x+7) \,dx By signing up, you'll get thousands of step-by-step solutions to your homework...
)dxAns:3x−x 2 /2+2x 3 /3+C B7. (1+x+x 2 +···+x n−1 )dxAns:x+x 2 /2+x 3 /3+···+x n /n+C B8. (3−cosx+3x 2 )dxAns:3x−sinx+x 3 +C B9. (sec 2 x+5sinx)dxAns:tanx−5cosx+C B10. (x+1/x)dxAns:x 2 /2+ln|x|+C B11. (2csc...
(18) 1 √ x±a dx=2 √ x±a (19) 1 √ a−x dx=−2 √ a−x 2 (20) x √ x−adx= 2a 3 (x−a) 3/2 + 2 5 (x−a) 5/2 ,or 2 3 x(x−a) 3/2 − 4 15 (x−a) 5/2 ,or 2 15 (2a+3x)(x−a) 3/2 (21) √ ax+bdx= 2b 3a + 2x 3 ...
常用积分表（Common integral table）Common integral formula (a) containing the integral (axb+0a =) Formula 1.dxaxb+ = 1lnaxbCa++ 2. = (axbx) + 11 (formula)(1)AxbCa + + + Mu + (U = 1.)3.dxxaxb+ = formula 21 (LN) axbbaxbCa+.++ The 4.2dxxaxb+ formula (2) = 22311 (...