2.8万 35 7:24 App 有理函数不定积分4 Integral of 1/(x^6 + 1) dx 1.9万 20 4:25 App 求不定积分 Integral of Sqrt[tanx] dx 1.7万 24 4:52 App 多种方法计算积分 Integral of secx dx 2.2万 20 5:26 App 计算sin18°, cos18°, sin36°, cos36°, sin54°, cos54°, sin72°...
1158 1 4:16 App 求不定积分 ∫(sec^2 x)/(secx + tanx)^(9/2) dx 1722 -- 5:32 App 求不定积分∫Sqrt[x^2 - 2 x + 2] dx 3248 2 3:01 App 比较简单的积分练习题 Integral of sin (lnx) dx 7643 6 4:32 App 求所有的质数 p, q ,满足 p^q + q^p 是质数 7224 10 3...
Integrate: integral of (sec^2 x)/(3 + tan^2 x) dx. Evaluate the following integral. (a) \int sec^2x \space tanx dx (b) \int (x^3 +x)^{10}(3x^2 + 1) dx Find the antiderivative of the following function. f(x) = tanx Integral of x tan(x^2) dx Evaluate the integral ...
Evaluate the integral. \int \frac{sin(tanx)}{cos^2x} dx Evaluate the integral of (9x-2)^(-3) dx. Evaluate the integral from 2 to 4 of x*sqrt(x - 2) dx. Evaluate the integral: int_{0}^{3} mid x-2 mid dx. Evaluate the integral of 3x^2 cos(3x) dx. ...
∫1secx+tanxdx= View Solution ∫secxlog(secx+tanx)dx= View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
Answer and Explanation:1 We are given: {eq}\displaystyle \int_{0}^{\frac{\pi }{2}}\sin ^{3}\ x\cos ^{2}\ x \ dx {/eq} Compute the indefinite integral: {eq}=\displaystyle... Learn more about this topic: Applying the Rules of Differentiation to Calculate Derivatives ...
∫ sec2x dx = tanx + C ∫ sec x tan x dx = sec x + C ∫ cosec x cot x dx = -cosec x + C ∫1/(√(1-x2))= sin-1x + C ∫-1/(√(1-x2))= cos-1x + C ∫1/(1+x2)= tan-1x + C ∫-1/(1+x2)= cot-1x + C ...
59. [T] y=tanxy=tanx over the interval [0,π4][0,π4]; the exact solution is 2ln(2)π2ln(2)π. 60. [T] y=x+1√4−x2y=x+14−x2 over the interval [−1,1][−1,1]; the exact solution is π6π6. Show Solution In the following exercises, compute the...
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常用积分表（Common integral table）Common integral formula (a) containing the integral (axb+0a =) Formula 1.dxaxb+ = 1lnaxbCa++ 2. = (axbx) + 11 (formula)(1)AxbCa + + + Mu + (U = 1.)3.dxxaxb+ = formula 21 (LN) axbbaxbCa+.++ The 4.2dxxaxb+ formula (2) = 22311 (...