With them we can write the trigonometric expressions in a convenient way when operating expressions, which should be taken into account when solving the integrals. Answer and Explanation: Rewritten the integral in terms of sine and cosine: ∫tan2xdx=∫sin2xcos2xdx Us...Become...
What is the integral of x/(x - 2)? If f(x) = integral e^x dx and f (0) = 2, then what is f(2)? a) e^2. b) e^2 - 1. c) e^2 + 1. d) e + 2. What is the Integral of tan^5(x) dx? If integral_{-60}^{-30} f (x) dx = 15 and integral_{-60}^{-...
(∫ (sec)(x)+(tan)(x)dx) 相关知识点: 试题来源: 解析 Split the single integral into multipleintegrals. (∫ (sec)(x)dx+∫ (tan)(x)dx) The integral of ( (sec)(x)) with respect to ( x) is ( (ln)(|(sec)(x)+(tan)(x)|)). ( (ln)(|(sec)(x)+(tan)(x)|)+C+∫...
Evaluate the integral: integral from 0 to pi/4 of sin^6(3y) cos^5(3y) dy. Evaluate the following integral: integral_{-fraction {pi}{4^{fraction {pi}{4 \frac {x^2 tan x}{1 + sin^4 x} dx Evaluate the given integrals. a. \int_{-1}^{1} |2x-1|dz b. \int_{0}...
Answer to: Evaluate the Integral \int \tan^2 x \sec^3 x \, dx By signing up, you'll get thousands of step-by-step solutions to your homework...
∫ tan^3x/cos^4xdx =∫ tan^3x*sec^4xdx =∫ tan^3x*(tan^2x+1)*sec^2xdx 令u=tanx du=sec^2xdx =∫u^3(u^2+1)du =∫(u^5+u^3)du =1/6u^6+1/4u^4+C =1/6 tan^6x+1/4tan^4x+C
( x+C-2((tan)(x)+C)+∫ ((sec))^4(x)dx) Simplify the expression. ( x+C-2((tan)(x)+C)+∫ ((sec))^2(x)((sec))^2(x)dx) Using the Pythagorean Identity, rewrite ( ((sec))^2(x)) as ( 1+((tan))^2(x)). ( x+C-2((tan)(x)+C)+∫ (1+((tan))^2(...
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Evaluate the definite integrals ∫π40cosecxdx View Solution ∫ sinx dx View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...
What is the integral of 1/tan(x) dx?Integrals of Trigonometric Functions:For the six trigonometric functions, we have formulas for their integrals. These formulas are extremely useful, but it is also useful to be able to calculate these integrals without using the formula. This way, even if...