Answer to: Evaluate the integral: integral of tan^2(x) sec(x) dx. By signing up, you'll get thousands of step-by-step solutions to your homework...
What is the integral of x/(x - 2)? If f(x) = integral e^x dx and f (0) = 2, then what is f(2)? a) e^2. b) e^2 - 1. c) e^2 + 1. d) e + 2. What is the Integral of tan^5(x) dx? If integral_{-60}^{-30} f (x) dx = 15 and integral_{-60}^{-...
哈哈,第二个积分目测就能看出答案,第一个确实有点困难。up出这个对比应该是想表达,两个不定积分形式上虽然有点像,但是实际上结果差异是很大的。 2022-01-22 17:023回复 故事说给枕头听- 第一题分子分母同除cos²x,分子凑微分dtanx,分母sec²x利用三角恒等式化为tan²x+1分母就是2tan²x+1然后套...
(∫ (sec)(x)+(tan)(x)dx) 相关知识点: 试题来源: 解析 Split the single integral into multipleintegrals. (∫ (sec)(x)dx+∫ (tan)(x)dx) The integral of ( (sec)(x)) with respect to ( x) is ( (ln)(|(sec)(x)+(tan)(x)|)). ( (ln)(|(sec)(x)+(tan)(x)|)+C+∫...
An Integral Image is a transformed representation of an input image, where each pixel value corresponds to the sum of pixel values in a rectangular region of the original image. This transformation allows for efficient computation of the sum of pixel values in any given rectangular block of the...
∫sin2(x)cos(x)dx (Use C as the arbitrary constant.) U-Substitution:One of the many different integration methods is u-substitution. As its name suggests, it employs the variable u as a transient substitute. An appropriate substitution could possibly convert ...
Evaluate the integral \int \frac{\text{d}x}{\sqrt{9 8x x^2 . Evaluate the integral. \int 8\sec ^{3}xdx Evaluate the integral of sec^3 3x * tan^5 3x dx. Evaluate the integral. \int \tan^4 \theta \sec^6 \theta d\theta ...
II. On the integral ∫dx/x, and on some consequences that have been deduced from itdoi:10.1080/14786444808645914YoungJ.R.Taylor & Francis GroupPhilosophical Magazine
A direct derivation of the Fourier transform of the integral of a function of time f(t) in terms of the Fourier transform of f(t) is presented. The presentation differs from the standard derivation found in text books and does not make use of the principle of convolution....
∫ tan^3x/cos^4xdx =∫ tan^3x*sec^4xdx =∫ tan^3x*(tan^2x+1)*sec^2xdx 令u=tanx du=sec^2xdx =∫u^3(u^2+1)du =∫(u^5+u^3)du =1/6u^6+1/4u^4+C =1/6 tan^6x+1/4tan^4x+C