Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 解析 嘻嘻,最近因为马上要面试,就回忆一下树的遍历,快排,最长公共子序列,八皇后之类的基...
链接:https://leetcode-cn.com/problems/binary-tree-inorder-traversal python # 0094.二叉树中序遍历 # 递归 & 迭代 class Solution: def inOrderRecur(self,head: TreeNode) -> int: """ 递归遍历,LNR, 左根右 :param head: :return: """ def traversal(head): # 递归终止条件 ifhead== None: ...
ref:Morris Traversal方法遍历二叉树(非递归,不用栈,O(1)空间) wiki:Threaded binary tree A binary tree isthreadedby making all right child pointers that would normally be null point to the inorder successor of the node (ifit exists), and all left child pointers that would normally be null poi...
题目描述英文版描述Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: []…
Leetcode 之Binary Tree Inorder Traversal(43) 树的中序遍历。先不断压入左结点至末尾,再访问,再压入右结点。注意和先序遍历的比较 vector<int> inorderTraversal(TreeNode *root) { vector<int>result; stack<TreeNode *>s; TreeNode*p =root;while(!s.empty() || p !=nullptr)...
题目地址:https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/ 题目描述 Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. ...
binary_tree_level_order_traversal_102 fix: imports to correct package Mar 28, 2020 binary_tree_maximum_path_sum_124 fix: imports to correct package Mar 28, 2020 climbing_stairs_70 docs: update readme Mar 28, 2020 coin_change_322
名字叫做, morrois traversal, 自己写了下: My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicList<Integer>inorderTraversal(TreeNoderoot){List...
Pre-Order Traversal 三种解法: Recursive Iterate 用Stack Morris Traversal (好处是,Pre-Order和In-Order代码只有很小的改动) Morris Pre-Order Traversal (LeetCode 144) (Medium) 1...If left child is null, print the current node data. Move to right child. ...
you'll often need some way to get access to each object in the collection. In fact, depending on the collection, you may want several ways to access each object such as front to back, back to front, preorder or postorder. To keep the collection simple, the traversal code itself is oft...