Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 解析 嘻嘻,最近因为马上要面试,就回忆一下树的遍历,快排,最长公共子序列,八皇后之类的基...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> inorderTraversal(TreeNode*root) { vector<int>ret;if( !root )returnret; stack<TreeNode*>sta; sta.push(root);while( !sta.empty() ) { TreeNode*tmp =sta.top(); sta.pop();if(...
* @return: Inorder in ArrayList which contains node values. */// 由于主函数的形式已经符合分治法需要的形式(具有合适的返回值),直接使用主函数做为递归函数vector<int>inorderTraversal(TreeNode * root){// write your code herevector<int> result;if(root == nullptr) {returnresult;// 递归三要素之...
Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
Given a binary tree, return theinordertraversal of its nodes' values. 示例: 代码语言:javascript 代码运行次数:0 AI代码解释 输入:[1,null,2,3]1\2/3输出:[1,3,2] 进阶:递归算法很简单,你可以通过迭代算法完成吗? Follow up:Recursive solution is trivial, could you do it iteratively?
12 vector<int> inorderTraversal(TreeNode *root) { 13 vector<int> res; 14 if(root==NULL) return res; 15 stack<TreeNode*> s; 16 TreeNode* cur=root; 17 while(cur||!s.empty()){ 18 while(cur!=NULL){ 19 s.push(cur); 20 cur=cur->left; ...
In a postorder traversal of the vertices of T, we visit the vertices of T1 in postorder, then the vertices of T2 in postorder and finally we visit r. Now you are given the preorder sequence and inorder sequence of a certain binary tree. Try to find out its postorder sequence. ...
Integer>result=newArrayList<Integer>();if(root==null)returnresult;inorderTraversal(root,result);returnresult;}privatevoidinorderTraversal(TreeNode root,ArrayList<Integer>result){if(root.left!=null)inorderTraversal(root.left,result);result.add(root.val);if(root.right!=null)inorderTraversal(root....
本题链接:Binary Tree Inorder Traversal 本题标签:Tree, Hash Table, Stack 本题难度: 方案1: 时间复杂度: 空间复杂度:
Unfortunately, the .NET Framework does not contain a binary tree class, so in order to better understand binary trees, let's take a moment to create our own binary tree class. The First Step: Creating a Base Node Class The first step in designing our binary tree class is to create a ...