1classSolution {2public:3vector<int> preorderTraversal(TreeNode *root) {4vector<int>result;5TreeNode *p =root;6while(p) {7if(!p->left) {8result.push_back(p->val);9p = p->right;10}else{11TreeNode *q = p->left;12while(q->right && q->right !=p) {13q = q->right;14}1...
原题链接在此:https://leetcode.com/problems/binary-tree-level-order-traversal/ Given therootof a binary tree, returnthe level order traversal of its nodes' values. (i.e., from left to right, level by level). 给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访...
Leetcode 144 binary tree preorder traversal 下面这种写法使用了一个辅助结点p,这种写法其实可以看作是一个模版,对应的还有中序和后序的模版写法,形式很统一,方便于记忆。 辅助结点p初始化为根结点,while循环的条件是栈不为空或者辅助结点p不为空,在循环中首先判断如果辅助结点p存在,那么先将p加入栈中,然后将...
Leetcode 94: Binary Tree Inorder Traversal-中序遍历 自动驾驶搬砖师 一步一个台阶,一天一个脚印 一、题目描述 给定一个二叉树,返回它的中序遍历。 二、解题思路 2.1 递归法 时间复杂度 O(n) 空间复杂度 O(n) 2.2 迭代法 时间复杂度 O(n) 空间复杂度 O(n)(1) 同理创建一个Stack,然后按左/中/右...
Below is the code for theBinaryTreeclass. public class BinaryTree<T> { private BinaryTreeNode<T> root; public BinaryTree() { root = null; } public virtual void Clear() { root = null; } public BinaryTreeNode<T> Root { get { return root; } set { root = value; } } } ...
Below is the code for theBinaryTreeclass. public class BinaryTree<T> { private BinaryTreeNode<T> root; public BinaryTree() { root = null; } public virtual void Clear() { root = null; } public BinaryTreeNode<T> Root { get { return root; } set { root = value; } } } ...
** Inorder Traversal: left -> root -> right ** Preoder Traversal: root -> left -> right ** Postoder Traveral: left -> right -> root 记忆方式:order的名字指的是root在什么位置。left,right的相对位置是固定的。 图片来源:https://leetcode.com/articles/binary-tree-right-side-view/ ...
Pre-Order Traversal 三种解法: Recursive Iterate 用Stack Morris Traversal (好处是,Pre-Order和In-Order代码只有很小的改动) Morris Pre-Order Traversal (LeetCode 144) (Medium) 1...If left child is null, print the current node data. Move to right child. ...
103.binary-tree-zigzag-level-order-traversal Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree [3,9,20,null,null,15,7],...
Leetcode: Closest Binary Search Tree Value empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target....