1classSolution {2public:3vector<int> preorderTraversal(TreeNode *root) {4vector<int>result;5TreeNode *p =root;6while(p) {7if(!p->left) {8result.push_back(p->val);9p = p->right;10}else{11TreeNode *q = p->left;12while(q->right && q->right !=p) {13q = q->right;14}1...
原题链接在此:https://leetcode.com/problems/binary-tree-level-order-traversal/ Given therootof a binary tree, returnthe level order traversal of its nodes' values. (i.e., from left to right, level by level). 给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访...
vector<int> inorderTraversal(TreeNode* root) { vector<int> vec; if(root == NULL)return vec; inorder(root,vec); return vec; } }; 递归 class Solution { public: void inorder(TreeNode* root, vector<int> & vec) { if(root -> left != NULL) { inorder(root -> left,vec); } vec...
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> inorderTraversal(TreeNode* root) { vector<int> ret; if(...
Below is the code for theBinaryTreeclass. public class BinaryTree<T> { private BinaryTreeNode<T> root; public BinaryTree() { root = null; } public virtual void Clear() { root = null; } public BinaryTreeNode<T> Root { get { return root; } set { root = value; } } } ...
Below is the code for theBinaryTreeclass. public class BinaryTree<T> { private BinaryTreeNode<T> root; public BinaryTree() { root = null; } public virtual void Clear() { root = null; } public BinaryTreeNode<T> Root { get { return root; } set { root = value; } } } ...
** Inorder Traversal: left -> root -> right ** Preoder Traversal: root -> left -> right ** Postoder Traveral: left -> right -> root 记忆方式:order的名字指的是root在什么位置。left,right的相对位置是固定的。 图片来源:https://leetcode.com/articles/binary-tree-right-side-view/ ...
Pre-Order Traversal 三种解法: Recursive Iterate 用Stack Morris Traversal (好处是,Pre-Order和In-Order代码只有很小的改动) Morris Pre-Order Traversal (LeetCode 144) (Medium) 1...If left child is null, print the current node data. Move to right child. ...
LeetCode: 331. Verify Preorder Serialization of a Binary Tree 题目描述 One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node’s value. If it is a null node, we record using a sentinel value such as #. ...
auto mid= first + length /2; TreeNode*root =newTreeNode(*mid); root->left =sortedArrayToBST(first, mid); root->right =sortedArrayToBST(mid, last);returnroot; } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. View Code...