“function declaration isn't a prototype”警告的含义 这个警告信息表明在C或C++代码中,函数的声明没有使用函数原型(function prototype)。函数原型是指在函数声明时明确指出函数的返回类型、函数名和参数类型。没有使用函数原型可能会导致类型不匹配的问题,进而在编译时产生错误或运行时出现未定义行为。 可能导致该警告...
C编译报错: implicit declaration of function xxx is invalid in C99 [-Wimplicit-function-declaration] 代码文件 test.c,内容如下: 当前clang版本如下: 当前gcc版本如下: 执行编译报错 错误: implicit declaration of function ‘sum’ ...猜你喜欢Pre
error:functiondeclarationisn’taprototype[-Werror=strict-prototypes]uint32_tsysctl_get_p() 原因:之前用的arm4.4.3编译链没报错,后面用的gcc-linaro6.5.0报错,看来是不同编译链的规则导致。函数无参数,不能空着,需要加void: uint32_t sysctl_get_p(void)...
解决办法是:即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning。
Q: function declaration isn't a prototype A: http://hi.baidu.com/%D4%BC%D0%DE%D1%C7ing/blog/item/d5f86a0f598b47c27acbe138.html static void cut_mode(void) 如果写成static void cut_mode() 就会有警告function declaration isn't a prototype...
function declaration isn't a prototype解决办法,即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
"warning: function declaration isn't a prototype" was caused by the function like that: return_type XXX() { ... } Please just modify the input paramter to void.return_type XXX(void) { ... } Or turn off the warning with -Wno-strict-prototypes (or simply by omitting -Wstrict-prototype...
./ir.c:45: warning: function declaration isn't a prototype 虽然不是error,但总不顺眼.应该如何...
a function declaration without a prototype is deprecated in all versions of C [-Werror,-Wstrict-prototypes] static inline uint32_t calc_local_lsr_now() ^ void src/switch_rtp.c:3497:33: error: a function declaration without a prototype is deprecated in all versions of C [-Werror,-Wstrict...
/u01/oracle/11/rdbms/public/ociap.h:10794: warning: function declaration isn’t a prototype creating build/lib.linux-x86_64-2.6 gcc -pthread -shared -Wl,-O1 -Wl,-Bsymbolic-functions build/temp.linux-x86_64-2.6/cx_Oracle.o -L/u01/oracle/11/lib -L/u01/oracle/11 -lclntsh -o build/...