在C语言中,遇到“function declaration isn't a prototype”的警告,通常意味着函数声明没有使用函数原型。以下是对该问题的详细解答: 解释什么是函数原型(function prototype): 函数原型是指在函数声明时明确指出函数的返回类型、函数名和参数类型。函数原型有助于编译器在编译阶段检查函数调用中的类型匹配问题,从而提高...
error:functiondeclarationisn’taprototype[-Werror=strict-prototypes]uint32_tsysctl_get_p() 原因:之前用的arm4.4.3编译链没报错,后面用的gcc-linaro6.5.0报错,看来是不同编译链的规则导致。函数无参数,不能空着,需要加void: uint32_t sysctl_get_p(void)...
"warning: function declaration isn't a prototype" was caused by the function like that: return_type XXX() { ... } Please just modify the input paramter to void.return_type XXX(void) { ... } Or turn off the warning with -Wno-strict-prototypes (or simply by omitting -Wstrict-prototype...
./ir.c:45: warning: function declaration isn't a prototype 虽然不是error,但总不顺眼.应该如何...
function declaration isn't a prototype解决办法,即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
Q: function declaration isn't a prototype A: http://hi.baidu.com/%D4%BC%D0%DE%D1%C7ing/blog/item/d5f86a0f598b47c27acbe138.html static void cut_mode(void) 如果写成static void cut_mode() 就会有警告function declaration isn't a prototype...
warning: function declaration isn’t a prototype(函数声明不是原型)的解决办法 linux驱动中定义一个无参的函数 int probe_num() { ... } 警告:函数声明不是一个原型 [-Wstrict-prototypes] 应对方法: 改成 int probe_num( void) { ... } 警告...
Function declaration isn't a prototype [-Wstrict-prototypes]espressif/arduino-esp32#3591 Closed TD-eradded a commit to TD-er/ESPEasy that referenced this issueDec 22, 2019 [PIO] Use -Wstrict-prototypes for C warnings c8da61c TD-ermentioned this issueDec 22, 2019 ...
Hi, We've been using j2objc for many years to great effect. We've recently started noticing this warning and i'm getting complaints from our iOS developers about it. It seems to reference to a great many j2objc generated classes, and is ...
printf("%d\t", jj); ++ii; } printf("\n"); June 29, 2005 c 2005 - Gopi Goswami (goswami@stat.harvard.edu) Page 6 ccr2005@stat.harvard.edu C-C++-R .stat.harvard.edu/˜ccr2005 ' & $ % Aside II • note, in such a case the variables declaration should be the first lin...