在C语言中,遇到“function declaration isn't a prototype”的警告,通常意味着函数声明没有使用函数原型。以下是对该问题的详细解答: 解释什么是函数原型(function prototype): 函数原型是指在函数声明时明确指出函数的返回类型、函数名和参数类型。函数原型有助于编译器在编译阶段检查函数调用中的类型匹配问题,从而提高...
error:functiondeclarationisn’taprototype[-Werror=strict-prototypes]uint32_tsysctl_get_p() 原因:之前用的arm4.4.3编译链没报错,后面用的gcc-linaro6.5.0报错,看来是不同编译链的规则导致。函数无参数,不能空着,需要加void: uint32_t sysctl_get_p(void)...
"warning: function declaration isn't a prototype" was caused by the function like that: return_type XXX() { ... } Please just modify the input paramter to void.return_type XXX(void) { ... } Or turn off the warning with -Wno-strict-prototypes (or simply by omitting -Wstrict-prototype...
./ir.c:45: warning: function declaration isn't a prototype 虽然不是error,但总不顺眼.应该如何...
function declaration isn't a prototype解决办法,即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
Q: function declaration isn't a prototype A: http://hi.baidu.com/%D4%BC%D0%DE%D1%C7ing/blog/item/d5f86a0f598b47c27acbe138.html static void cut_mode(void) 如果写成static void cut_mode() 就会有警告function declaration isn't a prototype...
问Xcode 9中的"This function声明is not a prototype“警告EN这并不意味着没有争论。这意味着没有指定...
Warn if a function is declared or defined without specifying the argument types. (An old-style function definition is permitted without a warning if preceded by a declaration which specifies the argument types.) So I applied it also to my PlatformIO environment and came across a number of warni...
warning: function declaration isn’t a prototype(函数声明不是原型)的解决办法 linux驱动中定义一个无参的函数 int probe_num() { ... } 警告:函数声明不是一个原型 [-Wstrict-prototypes] 应对方法: 改成 int probe_num( void) { ... } 警告...
error: command 'gcc' failed with exit status 1;;;warning: function declaration isn’t a prototype ociap.h error: command 'gcc' failed with exit status 1 === ~# aptitude install python-dev build-essential === root@w:~# cd /data/workSpace/src_tools...