“function declaration isn't a prototype”警告的含义 这个警告信息表明在C或C++代码中,函数的声明没有使用函数原型(function prototype)。函数原型是指在函数声明时明确指出函数的返回类型、函数名和参数类型。没有使用函数原型可能会导致类型不匹配的问题,进而在编译时产生错误或运行时出现未定义行为。 可能导致该警告...
function declaration isn't a prototype解决办法,即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
error:functiondeclarationisn’taprototype[-Werror=strict-prototypes]uint32_tsysctl_get_p() 原因:之前用的arm4.4.3编译链没报错,后面用的gcc-linaro6.5.0报错,看来是不同编译链的规则导致。函数无参数,不能空着,需要加void: uint32_t sysctl_get_p(void)...
function declaration isn't a prototype解决办法,对以上程序,在编译驱动的时候会出现以下warning:在网上查到解决办法是:即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
这个程序我在WINAVR+AVRSTUDIO里编译，通过了。只是出现了两个警告。这句：#include<avr/delay.h> 改成：#include<util/delay.h> 剩下一个警告：# warning "F_CPU not defined for <util/delay.h>"不用理会。因为F_CPU 在接下来的语句里已经定义了。所以：你的编译出现的问题可能是编译器的...
Q: function declaration isn't a prototype A: http://hi.baidu.com/%D4%BC%D0%DE%D1%C7ing/blog/item/d5f86a0f598b47c27acbe138.html static void cut_mode(void) 如果写成static void cut_mode() 就会有警告function declaration isn't a prototype...
"warning: function declaration isn't a prototype" was caused by the function like that: return_type XXX() { ... } Please just modify the input paramter to void.return_type XXX(void) { ... } Or turn off the warning with -Wno-strict-prototypes (or simply by omitting -Wstrict-prototype...
Function declaration isn't a prototype [-Wstrict-prototypes]espressif/arduino-esp32#3591 Closed TD-eradded a commit to TD-er/ESPEasy that referenced this issueDec 22, 2019 [PIO] Use -Wstrict-prototypes for C warnings c8da61c TD-ermentioned this issueDec 22, 2019 ...
Hi, We've been using j2objc for many years to great effect. We've recently started noticing this warning and i'm getting complaints from our iOS developers about it. It seems to reference to a great many j2objc generated classes, and is ...
warning: function declaration isn’t a prototype(函数声明不是原型)的解决办法,linux驱动中定义一个无参的函数intprobe_num(){ ...}警告:函数声明不是一个原型[-Ws