Given a binary tree, flatten it to a linked list in-place. 题意分析 Input: binary tree Output: flattened tree Conditions:将一个二叉树压平为一个flatten 树,也就是一条斜线 题目思路 先将左右子树压平,然后将左子树嵌入到本节点与右子树之间。 AC代码(Python) 1#Definition for a binary tree node....
Given a binary tree, flatten it to a linked list in-place. 将二叉树展开成链表 [ ] (D:\dataStructure\Leetcode\114.png) 思路:将根节点与左子树相连,再与右子树相连。递归地在每个节点的左右孩子节点上,分别进行这样的操作。 代码 Copy classSolution(object):defflatten(self, root):ifroot ==None:...
publicvoidflatten(TreeNoderoot){Stack<TreeNode>toVisit=newStack<>();TreeNodecur=root;TreeNodepre=null;while(cur!=null||!toVisit.isEmpty()){while(cur!=null){toVisit.push(cur);// 添加根节点cur=cur.right;// 递归添加右节点}cur=toVisit.peek();// 已经访问到最右的节点了// 在不存在左节...
2. 前序遍历(栈+迭代方式) /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right;* TreeNode() : val(0), left(nullptr), right(nullptr) {}* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}* TreeNode(int x, Tree...
114. Flatten Binary Tree to Linked List 这道题自己一开始的做法是建立一个新链表然后再指向它,想到浪费空间看了题解 思路就是将左子树接在父节点的右子树上,将右子树接在左子树后,这样就是先序遍历的结果了 /** * Definition for a binary tree node....
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Hints: If you notice carefully in the flattened tree, each node's right child points...
click to show hints. Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order trave 这道题要求把二叉树展开成链表,根据展开后形成的链表的顺序分析出是使用先序遍历,那么只要是数的遍历就有递归和非递归的两种方法来求解,这里我们也用两种...
Can you solve this real interview question? Flatten Binary Tree to Linked List - Given the root of a binary tree, flatten the tree into a "linked list": * The "linked list" should use the same TreeNode class where the right child pointer points to the
Given a binary tree, flatten it to a linked list in-place. For example, Given 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1/\25/\ \346 The flattened tree should look like: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
* Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode flatten(TreeNode root) { // Start typing your Java solution below ...