Write a Java program to find the first non-repeating character in a string. Visual Presentation: Sample Solution: Java Code: // Importing necessary Java utilities.importjava.util.*;// Define a class named Main.publicclassMain{// Main method to execute the program.publicstaticvoidmain(String[]...
// Importing necessary Java utilitiesimportjava.util.*;// Main class SolutionpublicclassMain{// Main methodpublicstaticvoidmain(String[]args){// Declaring and initializing a stringStringstr1="google";// Printing the index of the first non-repeating character in the given stringSystem.out.println...
Finding the first non-repeating character in a string is a common programming problem. It involves finding the first character that appears only once in the string. This task helps understand how to manipulate strings and use basic data structures in Java. Problem Statement Given a str...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。 这次需要函数返回的找到的字符串,同时输入的字符串中还有大...
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. 解题思路: 开个26个数的数组,然后先对字符串过一遍,统计每个字母出现的次数,然后从头再国一遍,第一个...
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. 给一个字符串,返回第一个不重复的字符的index,要是没有的话就返回-1 //第一次做,感觉巨简单,设一个set,一旦contains,就用striing.indexOf()---还能用上不熟悉的函数,简直完...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符的位置(index),如果所有的字符在给定的字符串中都有重复的话,那么你应该返回 -1。 样例 下面给出...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。
LeetCode 387: 字符串中的第一个唯一字符 First Unique Character in a String 题目: 给定一个字符串,找到它的第一个不重复的字符,并返回它的索引。如果不存在,则返回 -1。 Given a string, find the first non-repeating character in it and return it’s index. If it doesn’t exist, return -1....
You are given a string str consisting of lowercase Latin letters. Find the first non-repeating character in str. Note: You have to traverse the string only once. See original problem statement here Tets Case: Input: prepbytes Output: 1 Explanation: In the string 'prepbytes', we start trave...