if (unique) { System.out.println("The first non-repeated character in the String is: " + str1.charAt(i)); break; } } } } Sample Output: The given string is: gibblegabbler The first non repeated character in String is: i Flowchart: Java Code Editor:Improve this sample solution and ...
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. 解题思路: 开个26个数的数组,然后先对字符串过一遍,统计每个字母出现的次数,然后从头再国一遍,第一个...
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. 给一个字符串,返回第一个不重复的字符的index,要是没有的话就返回-1 //第一次做,感觉巨简单,设一个set,一旦contains,就用striing.indexOf()---还能用上不熟悉的函数,简直完...
Given a string s, return the first non-repeating character in it and return its index. If it ...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。
英文 Given a strings, returnthe first non-repeating character in it and return its index. If it does not exist, return-1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。 这次需要函数返回的找到的字符串,同时输入的字符串中还有大...
Given a strings, returnthe first non-repeating character in it and return its index. If it does not exist, return-1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。 这次需要函数返回的找到的字符串,同时输入的字符串中还有大小写。
First Unique Character in a String Difficulty:easy More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/first-unique-cha ... Leetcode算法比赛---First Unique Character in a String 问题描述 Given a string, find the first non-repeating character in it and return it's index...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符的位置(index),如果所有的字符在给定的字符串中都有重复的话,那么你应该返回 -1。 样例 下面给出...
标签: Java Python 算法 收藏 LeetCode 387: 字符串中的第一个唯一字符 First Unique Character in a String 题目: 给定一个字符串,找到它的第一个不重复的字符,并返回它的索引。如果不存在,则返回 -1。 Given a string, find the first non-repeating character in it and return it’s index. If it...