public static void main(String[] args) { // Declare and initialize a string variable. String str1 = "gibblegabbler"; // Print the original string. System.out.println("The given string is: " + str1); // Loop through each character of the string. for (int i = 0; i < str1.lengt...
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. 解题思路: 开个26个数的数组,然后先对字符串过一遍,统计每个字母出现的次数,然后从头再国一遍,第一个...
英文 Given a string s, return the first non-repeating character in it and return its index. If...
char[] strArray = data.toCharArray(); String retStr = ""; if (data.length() == 1) { retStr = data; } for (int i = 0; i < strArray.length; i++) { String valStr = Character.toString(strArray[i]); String rData = data; rData = data.replace(valStr, ""); rData = rD...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。 这次需要函数返回的找到的字符串,同时输入的字符串中还有大...
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。
Given a strings, returnthe first non-repeating character in it and return its index. If it does not exist, return-1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符。 这个题目在随后的面试中又出来变种。 这次需要函数返回的找到的字符串,同时输入的字符串中还有大小写。
Given a string s, return the first non-repeating character in it and return its index. If it does not exist, return -1. 中文 针对给定的一个字符串 s,你需要写一个算法,返回给定字符串中不重复字符的位置(index),如果所有的字符在给定的字符串中都有重复的话,那么你应该返回 -1。 样例 下面给出...
标签: Java Python 算法 收藏 LeetCode 387: 字符串中的第一个唯一字符 First Unique Character in a String 题目: 给定一个字符串,找到它的第一个不重复的字符,并返回它的索引。如果不存在,则返回 -1。 Given a string, find the first non-repeating character in it and return it’s index. If it...
Find the first non-repeating character in str. Note: You have to traverse the string only once. See original problem statement here Tets Case: Input: prepbytes Output: 1 Explanation: In the string 'prepbytes', we start traversing from the first index(since first non repeating character is ...