the contiguous subarray[4,−1,2,1]has the largest sum =6. 1,注意解题方法,设置两个变量,current,用来纪录当前值,和Max比较,如果为负,就把它设置为0. packageLeetcode;publicclassMaximumSubarray {publicintmaxSubArray(int[] A) {intmax=0;intcurrent=0;for(inti=0;i<A.length;i++){ current+=A[i];if(current>max){ max=current; }if(c...
0053-maximum-subarray.py 0054-spiral-matrix.py 0055-jump-game.py 0056-merge-intervals.py 0057-insert-interval.py 0058-length-of-last-word.py 0062-unique-paths.py 0064-minimum-path-sum.py 0066-plus-one.py 0070-climbing-stairs.py 0071-simplify-path.py 0072-edit-dista...
[2382. 删除操作后的最大子段和](https://leetcode.cn/problems/maximum-segment-sum-after-removals/) [2334. 元素值大于变化阈值的子数组](https://leetcode.cn/problems/subarray-with-elements-greater-than-varying-threshold/description/) 10 [1562. 查找大小为 M 的最新分组](https://leetcode.cn/pro...
For example, in array[1, 2, 3, 1], 3 is a peak element and your function should return the index number 2. 1publicclassSolution {2publicintfindPeakElement(int[] num) {3intpeak =Integer.MIN_VALUE;4intres = 0;5for(inti = 1; i < num.length - 1; i++) {6if(num[i] > num[...
Demonstrate all the questions on LeetCode in the form of animation.(用动画的形式呈现解LeetCode题目的思路) - fanfind/LeetCodeAnimation
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Submit your solution:https://leetcode.com/problems/find-the-duplicat...
Data Structure Array: Find the Increasing subsequence of length three with maximum product http://www.geeksforgeeks.org/increasing-subsequence-of-length-three-with-maximum-product/
0152-maximum-product-subarray.rs 0153-find-minimum-in-rotated-sorted-array.rs 0155-min-stack.rs 0167-two-sum-ii-input-array-is-sorted.rs 0169-majority-element.rs 0179-largest-number.rs 0190-reverse-bits.rs 0191-number-of-1-bits.rs 0198-house-robber.rs 0199-binary-tree-right-side-view....
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