(y+3)²=9or,x²+6x+9+y²+6y+9=9∴x²+y²+6x+6y+9=0This is the rcquired cquation.Equation of a Circle through the Given Three Points Lct(h,k) be the centre of the givcn circle which passcs through P(x₁,y₁),Q(x₂,y₂) and R(x₃,y₃), then PC...
Let the equation of the general form of the required circle be x² + y² +2gx+ 2fy + c= 0...(i)According to the problem, the above equation of the circle passes throughthe points (1, 0), (-1, 0) and (0, 1). Therefore,1 + 2g+ c= 0...(ii)1 -2g+ C=0...(iii...
结果1 题目 Q. 3 Find the equation of circle passing through the point of intersection of the lines x + 3y = 0 and 2x -7y =0 whose centre is the point of intersection of lines x+y+1=0 and x-2y+4=0. 相关知识点: 试题来源: 解析 0=-x++ 反馈 收藏 ...
COn|5dep=(S_1-6) dcl2 2=(3,-t) let the centr of the circle be at Cith, lay racp-cdia Q ansiderop-cd o?ca? r c(hale) dsstace fir mula 9 Byusinθ (h-5)^2+(k+6)^2=(h-1)^2+(k-2)^2 5h2-wh+25+12+12k+3b=h2-2ht1+k2-4k+4 ic-8h+16k=56h-2k=7(I) MN_...
First, let's assume that we have two points on the circumference: $$P_1(6, 23)=(x_1, y_1) $$ And $$P_2(18, 7) =(x_2, y_2) $$ These points must be... Learn more about this topic: Equation of a Circle | Formula, Forms & Examples...
points only. Therefore, we can get two equations in terms of the two parameters from which the parameters can be obtained. We can also take the example of a circle passing through the origin, whose general equation is given by ${{x}^{2}}+{{y}^{2}}+2gx+2fy=...
Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了.答案 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x+7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC的直线为 y=x-3,BC的...
Let the equation of the required circle be .Since the circle passes through points and .Since the centre of the circle lies on line ,From equations (1) and (2), we obtainOn solving equations (3) and (4), we obtain and .On substituting the values of and in equation (1), we obtain...
How to find the radius of a circle from the given two-points? How to find the radius of a circle from the segment? How do you find the center and radius of the circle given (x - 3)^2 + (y - 1)^2 = 25? How do you find the radius of a circle with the equation x^2 + ...
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...