Circle:For any given three points, the distance of the points from the center of the circle are always equal. So, using distance formula between two points, the coordinates of center can be determined.Answer and Explanation: In this problem, we are given the three points. Let the points ...
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...
Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了. 相关知识点: 试题来源: 解析 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x 7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC...
Find the equation of the circle which passes through the points (3,7),... 04:24 Show that the points (3,-2), (1,0), (-1, -2) and (1,-4) are con-cyclic... 08:04 Show that the points A(5,5), B(6,4), C(-2,4) and D(7,1) all lies on t... 06:57Exams...
Find the equation of the circle with: centre (0,-1) and radius 1. View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
2) Find the area of the circle of the above problem?Equation of a Circle:(i) A circle is the set of all points which are equidistant from a fixed point. That fixed point is called the center. The distance from the center to any point o...
Find an equation of the circle that has center (-3,3)and passes through (4,-1). 相关知识点: 试题来源: 解析 x^2+y^2+6x-6y=47 r=√((x_2-x_1)^2+(y_2-y_1)^2) (x+3)^2+(y-3)^2=(√5)^2 (x^2+y^2+6x-6y-6x-11)/(x^2+y^2+6x.6y=0.7) M ...
Let the equation of the required circle be .Since the circle passes through points and .Since the centre of the circle lies on line ,From equations (1) and (2), we obtainOn solving equations (3) and (4), we obtain and .On substituting the values of and in equation (1), we obtain...
To find the equation of the circle that passes through the points (4, 1) and (6, 5) and whose center lies on the line4x+y=16, we can follow these steps: Step 1: General Equation of the Circle The general equation of a circle with center(h,k)and radiusris given by: ...
To find the equation of the circle with a radius of 5 units that is tangent to the line 3x+4y−16=0 at the point (4, 1), we can follow these steps: Step 1: Identify the point of tangency and the radiusThe point of tangency is given as (4, 1). The radius of the circle is...