How do you find the equation of a circle given the endpoints of the diameter of the circle? How do you find the equation of a circle from the endpoints of the diameter? How do you find the equation of a circle using endpoints of the diameter?
Method 1 : Since the circle is tangent to both axes, the center of the circle is on the line. shing \(5_1-3_1=8x±y=0. b \(x=4y=4. \(x=1y=-1. Therefore the equation of the cirele is (x -4)+ (y-4)2=16 or(x-1)2+(y+1)2=1. Method 2: Let the equation of ...
Since the circle passes the origin, we let the equa- t ionbex^2+y^2+Dx+Ey=0 . We know that the circle passes points(a, 0), (0, b). Soa^2+Da=0andb^2+Eb=0 . Since a≠0, b=0, So D =-a, E =-b. The equation of the circl isx^2+y^2-ax-by=0 . ...
To find the equation of the circle that passes through the origin and cuts the given circles orthogonally, we can follow these steps:Step 1: General Form of the Circle The general equation of a circle can be expressed as: \( x^
Step 1: General Equation of the Circle The general equation of a circle with center(h,k)and radiusris given by: (x−h)2+(y−k)2=r2 Step 2: Substitute Point (4, 1) Since the circle passes through the point (4, 1), we substitutex=4andy=1into the circle's equation: ...
Find the equation of the circle with the given center and radius. Center at {eq}~(0, 0) {/eq} ; radius = {eq}5 {/eq} Circle and Its Equation A closed two-dimensional planner geometry that is associated with a constant distance from a fixed point on the pl...
Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了. 相关知识点: 试题来源: 解析 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x 7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC...
.Since the circle passes through points and .Since the centre of the circle lies on line ,From equations (1) and (2), we obtainOn solving equations (3) and (4), we obtain and .On substituting the values of and in equation (1), we obtainThus, the equation of the required circle ...
To find the equation of the circle that is concentric with the given circle 2x2+2y2−6x+8y+1=0 and has double its area, we will follow these steps: Step 1: Rewrite the given circle equation in standard formFirst, we divide the entire equation by 2 to simplify it:x2+y2−3x+4y...
To find the equation of the circle with center (0, -1) and radius 1, we can follow these steps:Step 1: Identify the center and radius The center of the circle is given as (0, -1) and the radius is given as 1.Step