Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了. 相关知识点: 试题来源: 解析 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x 7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC...
Since the circle passes the origin, we let the equa- t ionbex^2+y^2+Dx+Ey=0 . We know that the circle passes points(a, 0), (0, b). Soa^2+Da=0andb^2+Eb=0 . Since a≠0, b=0, So D =-a, E =-b. The equation of the circl isx^2+y^2-ax-by=0 . ...
Circle:For any given three points, the distance of the points from the center of the circle are always equal. So, using distance formula between two points, the coordinates of center can be determined.Answer and Explanation: In this problem, we are given the three points. Let the points ...
To find the equation of the circle that passes through the points (4, 1) and (6, 5) and whose center lies on the line4x+y=16, we can follow these steps: Step 1: General Equation of the Circle The general equation of a circle with center(h,k)and radiusris given by: ...
Find the equation of the circle having its centre on the line x + 2y - 3 = 0 and passing through the points of intersection of the circles x^2 + y^2 - 2x -4y + 1 = 0 and x^2 +y^2 - 4x - 2y + 1 = 0. Find the equation ...
Method 1 : Since the circle is tangent to both axes, the center of the circle is on the line. shing \(5_1-3_1=8x±y=0. b \(x=4y=4. \(x=1y=-1. Therefore the equation of the cirele is (x -4)+ (y-4)2=16 or(x-1)2+(y+1)2=1. Method 2: Let the equation of ...
COn|5dep=(S_1-6) dcl2 2=(3,-t) let the centr of the circle be at Cith, lay racp-cdia Q ansiderop-cd o?ca? r c(hale) dsstace fir mula 9 Byusinθ (h-5)^2+(k+6)^2=(h-1)^2+(k-2)^2 5h2-wh+25+12+12k+3b=h2-2ht1+k2-4k+4 ic-8h+16k=56h-2k=7(I) MN_...
Find the equation of the circle with the given center and radius. Center at {eq}~(0, 0) {/eq} ; radius = {eq}5 {/eq} Circle and Its Equation A closed two-dimensional planner geometry that is associated with a constant distance from a fixed point on the pl...
To find the equation of the circle that passes through the origin and cuts off intercepts of 6 and 8 from the positive parts of the x and y axes respectively, we can follow these steps:Step 1: Write the general equation of the circle
To find the equation of the circle that is concentric with the given circle 2x2+2y2−6x+8y+1=0 and has double its area, we will follow these steps: Step 1: Rewrite the given circle equation in standard formFirst, we divide the entire equation by 2 to simplify it:x2+y2−3x+4y...