Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了. 相关知识点: 试题来源: 解析 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x 7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC...
Problem 22:Find the equation of the circle passingthrough the points A(1,2)and B(3,4)and intersectingthe x-axis at two points to form a chord of length of 6.Problem 22:Find the equation of the circle passing through the points A(1, 2) and B(3,4)and intersecting the x-axis at...
【解析】Solution:(x-4)^2+(y-4)^2=160r(x-1)^2+ (y+1)^2=1 Method 1:Since the circle is tangent to both axes, the center ofthe circle is on the line.Solving5x-3y=8;x±y=0. x=4;y=4. =4arx=1;y=-1.Therefore the equation of the circle is(x -4)2+(y-4)^2=160r...
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...
the circle passes the origin,we let the equa--|||-tion be x+y+Dx Ey=0.-|||-We know that the circle passes points (a,0),(0,-|||-b).-|||-So a2 Da=0 and 62+Eb=0.-|||-Since a≠0,b≠0,SoD=-a,E=-b.-|||-The equation of the circle is x+y-ax -by =0.优质...
above question, we are told that the curve passes between two points only. Therefore, we can get two equations in terms of the two parameters from which the parameters can be obtained. We can also take the example of a circle passing through the origin, whose general ...
题目Find the equation of a circle whose center lies on the linex+4=0, and is tangent to the y‑axis at (0,−2). 相关知识点: 试题来源: 解析 (x + 4)= + (y + 2)= = 16(x + 4)= + (y + 2)= = 16 反馈 收藏
Here, the centre of the given circle is at(4,-4). As the circle touches both the axes, its radius is 4 units. The equation of the circle is(x-h)²+(y-k)²=r²or,(x-4)²+{y-(-4)}²=4²or,(x-4)²+(y+4)²=16or,x²-8x+16+y²+8y+16=16or,x²...
百度试题 结果1 题目【题目】Find the equation of the circle that circumscribes the triangle in Erercise.P_1=(-2,1) P_2=(6,-5) P_3=(2,-7) 相关知识点: 试题来源: 解析 【解析】(x-2)^2+(y+2)^2=5^2 反馈 收藏
Find the equation of the circle passing through the points (4, 1) and (6, 5) and whose center is on the line {eq}4x + y = 16 {/eq}. Circle: Let {eq}(h,k) {/eq} be the center of the circle and let {eq}r {/eq} be the...