Let us begin with the equation, $${X^2} + {Y^2} = 1$$ (1) which represents the unit circle, over any number field. Regarding this equation, Dipendra Prasad asked the following questions. What are all the number fields K JOT which, equation (1) has a non trivial integral solution...
Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了. 相关知识点: 试题来源: 解析 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x 7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC...
How to find closest point on a circle to a line in 3D? Find the equation of a circle that goes through the points (-1, -5^{\frac{1}{2) and (3,-2^{\frac{1}{2). Find an equation of the circle passing through the points (2, 3), (-1, 6), and (5, 2...
Let the equation of the required circle be .Since the circle passes through points and .Since the centre of the circle lies on line ,From equations (1) and (2), we obtainOn solving equations (3) and (4), we obtain and .On substituting the values of and in equation (1), we obtain...
To find the equation of the circle that passes through the points (4, 1) and (6, 5) and whose center lies on the line4x+y=16, we can follow these steps: Step 1: General Equation of the Circle The general equation of a circle with center(h,k)and radiusris given by: ...
Find the equation of the circle which passes through the points (3,7),... 04:24 Show that the points (3,-2), (1,0), (-1, -2) and (1,-4) are con-cyclic... 08:04 Show that the points A(5,5), B(6,4), C(-2,4) and D(7,1) all lies on t... 06:57Exams...
The centre of the circle is (-4,-8).To find the radius of the circle:(split)CQ&=√((x_2-x_1)^2+(y_2-y_1)^2)\& =√((3-(-4))^2+(-5-(-8))^2)\& =√(49+9)=√58(split)So the circle has a radius of √58.The equation of the circle is:(x-a)^2+(y-b...
A circle is a two-dimensional object which can be used in the construction of a bridge, the light of a car/van, etc. The general equation of a circle having points(x1,y1)and(x2,y2)on the ends of a diameter is(x−x1)(x−x2)+(y−y1)(y−y2...
COn|5dep=(S_1-6) dcl2 2=(3,-t) let the centr of the circle be at Cith, lay racp-cdia Q ansiderop-cd o?ca? r c(hale) dsstace fir mula 9 Byusinθ (h-5)^2+(k+6)^2=(h-1)^2+(k-2)^2 5h2-wh+25+12+12k+3b=h2-2ht1+k2-4k+4 ic-8h+16k=56h-2k=7(I) MN_...
Move the two points and write the circle's equation in Cartesian and Polar Form. The points have restrictions on where they can be moved. Cartesian Form(x,y) =0 Polar Form(r,θ) =0 There are 3 steps to solve this one.