跳出条件为L>=R, 当nums[mid-1]>nums[mid]时,例如3,2,1 我们把R置为mid-1, 反之,则把L置为mid classSolution {publicintfindPeakElement(int[] nums) {if(nums.length==0 || nums==null)return0;intL = 0;intR = nums.length - 1;while(L<R){intmid = (L+R+1)>>>1;if(nums[mid-1]...
leetcode 162 Find Peak Element(二分法) A peak element is an element that is greater than its neighbors. Given an input array wherenum[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pe...
题解:二分查找,如果你发现某个元素比左边相邻的元素小,那么左边一定存在驼峰,同理,右边也是。通过这个规律就可以二分了。 class Solution { public: int findPeakElement(vector<int>& nums) { int l = 0; int r = nums.size()-1; while(l<=r) { int mid = (l+r)/2; if((mid+1==nums.size...
A peak element is an element that is greater than its neighbors. num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. num[-1] = num[n] = -∞.[1, 2, 3, 1], ...
http://siddontang.gitbooks.io/leetcode-solution/content/array/find_peak_element.html Paste_Image.png ** 总结: Array 凡是涉及到搜索的,而且要求复杂度是 log n 的, 一般都会涉及到, Binary Search!!! ** Anyway, Good luck, Richardo! 写出...
(midVal>leftVal&&midVal>rightVal){midIndex}elseif(midVal<leftVal){findPeakElement(nums,startIndex,leftIndex)}else{findPeakElement(nums,rightIndex,endIndex)}}}funmain(args:Array<String>){valinput=intArrayOf(1,2,4,2)valfindPeakElement=FindPeakElement()println(findPeakElement.findPeakElement(...
LeetCode: 162. Find Peak Element 又是一道加了锁,不能做的题。 只好做 162 咯。 题目描述 A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak el...Leet...
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A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. ...
Can you solve this real interview question? Find Peak Element - A peak element is an element that is strictly greater than its neighbors. Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple pea