Leetcode之二分法专题-162. 寻找峰值(Find Peak Element) 峰值元素是指其值大于左右相邻值的元素。 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引。 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可。 你可以假设 nums[-1] = nums[n] = -∞。 示例1: 输...
leetcode---Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array wherenum[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi...
Can you solve this real interview question? Find Peak Element - A peak element is an element that is strictly greater than its neighbors. Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple pea
https://leetcode.com/problems/find-peak-element/ 思路就是二分查找。如果mid在波峰的递减部分,那么e = mid - 1. 如果mid在波峰的递增部分,那么s = mid + 1. 如果mid在波峰,那么返回。 my code: 效率不高。 class Solution(object): def findPeakElement(self, nums): """ :type nums: List[int]...
题目链接:https://leetcode.com/problems/find-peak-element/题目: A peak element is an element that is greater than its neighbors. num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peak...
A peak element is an element that is greater than its neighbors.Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index.The array may contain multiple peaks, in that case return the index to any one of the peaks is fine....
http://siddontang.gitbooks.io/leetcode-solution/content/array/find_peak_element.html Paste_Image.png ** 总结: Array 凡是涉及到搜索的,而且要求复杂度是 log n 的, 一般都会涉及到, Binary Search!!! ** Anyway, Good luck, Richardo! 写出...
(midVal>leftVal&&midVal>rightVal){midIndex}elseif(midVal<leftVal){findPeakElement(nums,startIndex,leftIndex)}else{findPeakElement(nums,rightIndex,endIndex)}}}funmain(args:Array<String>){valinput=intArrayOf(1,2,4,2)valfindPeakElement=FindPeakElement()println(findPeakElement.findPeakElement(...
这种找Peak Element的首先想到的是binary search, 因为有更优的时间复杂度,否则brute forceO(n)的方法太直接了。 binary search的方法就是比较当前element与邻居,至于左邻居还是右邻居都可以,只要一致就行。不断缩小范围,最后锁定peak element. 这种类似题也有很多Follow up, 比如先增后减的数组怎么找指定元素,甚至...
LeetCode 162. Find Peak Element 简介:给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引。数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可。 Description A peak element is an element that is greater than its neighbors....