Can you solve this real interview question? Find Peak Element - A peak element is an element that is strictly greater than its neighbors. Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple pea
leetcode---Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array wherenum[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi...
题目链接:https://leetcode.com/problems/find-peak-element/题目: A peak element is an element that is greater than its neighbors. num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peak...
leetcode 162. Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in tha......
Leetcode: Find Peak Element 题目: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks...
LeetCode-162-Find Peak Element 算法描述: A peak element is an element that is greater than its neighbors. Given an input arraynums, wherenums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one ...
A peak element is an element that is greater than its neighbors.Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index.The array may contain multiple peaks, in that case return the index to any one of the peaks is fine....
LeetCode 162. Find Peak Element 简介:给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引。数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可。 Description A peak element is an element that is greater than its neighbors....
这种找Peak Element的首先想到的是binary search, 因为有更优的时间复杂度,否则brute forceO(n)的方法太直接了。 binary search的方法就是比较当前element与邻居,至于左邻居还是右邻居都可以,只要一致就行。不断缩小范围,最后锁定peak element. 这种类似题也有很多Follow up, 比如先增后减的数组怎么找指定元素,甚至...
LeetCode上的原题,请参见我之前的博客Find Peak Element。解法一:class Solution { public: /** * @param A: An integers array. * @return: return any of peek positions. */ int findPeak(vector<int> A) { int left = 0, right = A.size() - 1; while (left < right) { int mid = lef...