Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. SOLUTION 1: 这个题目trick的地方在于,它的旋转pivot次数未知。所以有可能它转...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 解法1:顺序查找,时间复杂度O(n)。 classSolution {public:intfindMin(vector<int>...
但这样会有一个问题的,对于下边的例子,就会遇到死循环了。 问题出在,当数组剩两个的时候,mid = (start + end)/ 2,mid取的就是start。上图的例子,mid > end, 更新start = mid,start位置并不会变化。那么下一次mid的值也不会变,就死循环了。所以,我们要更新start = mid + 1,同时也使得start指向了最...
Find the minimum element. You may assume no duplicate exists in the array. 本题难度Medium。 二分查找法 【复杂度】 时间O(N) 空间 O(N) 【思路】 题目假设:You may assume no duplicate exists in the array. 这道题与其他Rotated Sorted Array题一样可以用改良的二分查找法来做。 原则是只要一直...
www.lintcode.com/en/problem/find-minimum-in-rotated-sorted-array-ii/ 【题目解析】 此题可使用二分法。 与Find Minimum in Rotated Sorted Array对照看, 一共有两处修改。 1、在无重复元素时,首尾元素相等代表指向同一个位置,因此程序直接返回即可。
Leetcode Find Minimum in Rotated Sorted Array 题目大意: 对一个有序数组翻转, 就是随机取前K个数,移动到数组的后面,然后让你找出最小的那个数,注意,K有可能是0,也就是没有翻转。 毫无疑问,遍历一次肯定可以找到,但这样时间复杂度是O(n),如果你在面试的时候遇到这样的问题,你这样回答面试官肯...
双指针,一头从左走,一头从右走任意一头出现,当前数小于左边且小于右边时,找到最小值,注意取余符号获取邻接的左边数和右边数min_num处理特殊情况没用二分法,反正是通过了,不管了, class Solution: def find…
总结: Array, Binary Search ** Anyway, Good luck, Richardo! My code: publicclassSolution{publicint findMin(int[]nums){if(nums==null||nums.length==0)return0;intbegin=0;intend=nums.length-1;while(begin<end){int middle=(begin+end)/2;if(nums[middle]<nums[end]){end=middle;}else{//nu...
Here, we are going to find the solution to find the minimum in rotated sorted array with C++ implementation.
Solution: Algorithm: Java program to find minimum element in a sorted and rotated array : If you want to practice data structure and algorithm programs, you can go through data structure and algorithm interview questions. In this post, we will see how to find minimum element in sorted and ...