一、题目描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二、分析 这题难度有,因为他默认的是数组中所有的元素是不同的。只...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 这道题目就是Find Minimum in Rotated Sorted Array的增强版,在数组中增加了重复的元素。 具体的解法...
问题出在,当数组剩两个的时候,mid = (start + end)/ 2,mid取的就是start。上图的例子,mid > end, 更新start = mid,start位置并不会变化。那么下一次mid的值也不会变,就死循环了。所以,我们要更新start = mid + 1,同时也使得start指向了最小值。 综上,找最小值的代码就出来了。 publicintfindMin(...
Find the minimum element. You may assume no duplicate exists in the array. 本题难度Medium。 二分查找法 【复杂度】 时间O(N) 空间 O(N) 【思路】 题目假设:You may assume no duplicate exists in the array. 这道题与其他Rotated Sorted Array题一样可以用改良的二分查找法来做。 原则是只要一直...
publicintfindMin(int[]nums){intstart=0;intend=nums.length-1;while(start<end){intmid=(start+end)>>>1;if(nums[mid]>nums[end]){start=mid+1;}elseif(nums[mid]<nums[end]){end=mid;}else{//添加代码}}returnnums[start];} 可以想几个例子考虑下。
153. Find Minimum in Rotated Sorted Array 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element.
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums of unique elements, return the minimum element of this array. ...
My code: My test result: 这不是一个好方法。下面介绍 binary search 版方法。 My code: My test result: 一下子快...
Find the minimum element. The array may contain duplicates. 这道题是Search in Rotated Sorted Array的扩展,思路在Find Minimum in Rotated Sorted Array中已经介绍过了,和Find Minimum in Rotated Sorted Array唯一的区别是这道题目中元素会有重复的情况出现。不过正是因为这个条件的出现,影响到了算法的时间复...
154. Find Minimum in Rotated Sorted Array II 题目描述: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. Find the minimum element. The array may contain duplicates. Example 1: (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). ...